Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process:starting with any positive integer and replace the number by the Sum of the squares of its digits, and repeat the process until the number equals 1 (where it would stay), or it loops Endl essly in a cycle which does not include 1. Those numbers for which this process ends in 1 is happy numbers.
Example: is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
Solution:
Use loop to calcuate the square sum until meet one of the these of the stops:
1. Sum is 1, return true
2. Sum value got before, which means there is a sum loop and would never goes to 1. return False
public boolean ishappy (int n) { if (n<=0) return false; Set<long> records = new hashset<> (); Long ln = n; while (ln< integer.max_value) { if (records.contains (LN)) return false; else Records.add (LN); ln = getsquaresum (LN); if (ln = = 1) return true; } return false; } Public long getsquaresum (long N) { long sum = 0; while (n!=0) { sum+= Math.pow (n%10,2); n/=10; } return sum; }
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[LeetCode202] Happy number