Linux C pointer problem

char ch = ' a ';

Char *CP = &ch;

= ++*cp++;

How do you explain the third sentence?

= ++*cp++;

Should be illegal as an lvalue (on the left side of the equals sign), as the right value (that is, the right side of the equals sign), how to explain???

I've seen it, and the result is this:
=++ (* (cp++));
Due to the suffix, the system first produces a copy of the CP, then the CP original value indirectly accesses the content, then adds 1 to the content.
As a result, a becomes B.

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Linux C pointer problem