Map learning in C ++

Description:

Enter information about N students and then query them.

Input:

The first Act N entered, that is, the number of students (n <= 1000)

The next n rows contain information about N students. The information format is as follows: 01 Li Jiangnan 2102 Liu Tang male 2303 Zhang Jun male 1904 Wang na female 19 then input a m (M <= 10000 ), next, there will be m rows, representing M queries. Each row will enter a student ID in the following format: 02030104

Output:

Output m rows. Each row contains the information of a student corresponding to the query.

If no student information exists, "no answer!" Is output !"

Sample input:

401 Li Jiang male 2102 Liu Tang male 2303 Zhang Jun male 1904 Wang na female 1950203010403

Sample output:

02 Liu Tang male 2303 Zhang Jun male 1901 Li Jiang male 2104 Wang na female 1903 Zhang Jun male 19


A simple question.
It is used to practice C ++ map and string usage.
In any case, it's still easy to write without Java.

Learning statement:
1. Map <string, string >:: iterator ITER; // little understanding of C ++.

2、 m.insert(pair<string,string>(id,info));  

3. What is the name of the key and value respectively starting with ITER-> first ITER-> second //? To tell the truth, it's really frustrating. No wonder someone says C ++ is rubbish.

4. iter = M. Find (ID );

   if(iter != m.end()) 

 

#include <iostream>
#include <stdio.h>
#include <map>
#include <string>
using namespace std;

int main() {
string id,info,str;
int index,n,M;
    map<string,string> m;
    map<string,string>:: iterator iter;
while(cin >> n){
        cin.ignore();
        m.clear();
for(int i=0; i<n; i++){
            getline(cin,str);
            index = str.find(" ");
            id = str.substr(0,index);
            info = str.substr(index+1);
            m.insert(pair<string,string>(id,info));
        }
        cin >> M;
for(int i=0; i<M; i++){
            cin >> id;
            iter = m.find(id);
if(iter != m.end())
                cout << iter->first <<" "<<iter->second<<endl;
else
                 cout<<"No Answer!"<<endl;
        }
    }

return 0;
}