No! (Quick exam, do some simple questions)

No! Time limit:MS | Memory limit:65535 KB

Describe

Judgment: Two number x, y positive and negative properties.

Requirements: You cannot use the comparison operator, which is "<", ">", "<=", ">=", "= =", "! =".

Input

There are multiple sets of data, one row for each group of data, and two digits x, y for each row.
X, Y is guaranteed to be within the int range.

Output

One

row for each set of data output.
If the two number is a positive and a negative, the output "signs is opposite"
If the same is positive or negative, the output "signs is not Opposot"
If unsure, output "signs can ' t be sure"
Output does not include quotation marks

Sample input

1 1-1 1

Sample output

Signs is not opposotsigns is opposite

Int:

1#include <iostream>2#include <cstdio>3#include <cstdlib>4 using namespacestd;5 intMain ()6 {7     intn,m;8      while(cin>>n>>m)9     {Ten         if(! (nm)) Onecout<<"signs can ' t be sure\n"; A         Else if(! (M*n+abs (m*n ))) -cout<<"Signs is opposite\n"; -         Else thecout<<"signs is not opposot\n"; -     } -}

String

1#include <iostream>2#include <cstdio>3#include <cstdlib>4 using namespacestd;5 intMain ()6 {7     Charn[ the],m[ the];8      while(cin>>n>>m)9     {Ten         if(n[0]=='0'|| m[0]=='0') Onecout<<"signs can ' t be sure\n"; A         Else if((n[0]!='-'&&m[0]=='-')|| (n[0]=='-'&&m[0]!='-')) -cout<<"Signs is opposite\n"; -         Else thecout<<"signs is not opposot\n"; -     } -}

No! (Quick exam, do some simple questions)