Nyoj 698 A Coin problem (Fibonacci)

Source: Internet
Author: User

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Test instructions

Describe
One day,jiameier is tidying up the Room,and find some coins. Then she throws the coin to play. Suddenly,she thinks of a problem, that if throw n times coin, what many situations of no-continuous up of the coin. Hey,let ' s solve the problem.
Input
The first of input is a
integer T which stands for the number of test cases. For each test case, there was one integer n (1<=n<=1000000000) in a line, indicate the times of throwing coins.
Output
the number of all situations of no-continuous up of the coin, moduled by 10000.
Sample input
3123
Sample output
235
Source
SCU Programming Contest Preliminary
idea: A large number of Fibonacci.

Code:

#include <stdio.h>int main () {    int i;    int a[15010];    a[0]=0,a[1]=2,a[2]=3;    for (i=3;i<15010;i++)        a[i]= (a[i-1]+a[i-2])%10000;    int n;    scanf ("%d", &n);    while (n--)    {        int m;        scanf ("%d", &m);        printf ("%d\n", a[m%15000]%10000);    }    return 0;}
When you want to give up, think of what you persist until now!

Nyoj 698 A Coin problem (Fibonacci)

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