On the knowledge of C language parameter transfer

C is not like an object-oriented language, there are no overloads, no overrides.

C language passed parameters if it is a pointer, it is only an address, remember just the address.

#include <stdio.h>
#include <stdlib.h>

void Test (char *buf, int len)
{
        printf sizeof ( BUF) =%d, len=%d\n ", sizeof (BUF), Len);
}
int main (void)
{
        char buf[10];
        Test (buf, sizeof (BUF));
        return 0;
}

weeds@weeds-laptop:~/love$./param
sizeof (BUF) =4, len=10

The results of the implementation are as follows.

Analysis of the reasons:

BUF[10], located in memory on the heap, is a contiguous area of memory.

My theoretical knowledge can not explain this, who explained the next chant.