PHP converts a date string to the current number of days.

PHP converts a date string to the current number of days as an example and input a date string. for example, 2011-3-23 outputs the current number of days as an example. for example: 1? Code :? PublicstaticfunctionconvertDateToLong ($ dateStr) {$ checkPattern ^ d {4} (-d {1, 2}) {2}) | ((. PHP converts a date string to an example of the current number of days

Enter a date string, for example, 2011-3-23.

The output is the current number of days, for example, 1.

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Code:

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    public static function convertDateToLong($dateStr){        $checkPattern = "/^\d{4}(((-\d{1,2}){2})|((\.\d{1,2}){2})|((\/\d{1,2}){2}))$/";        $date = substr(trim($dateStr),0,strpos(trim($dateStr)," ")>0 ? strpos(trim($dateStr)," ") : strlen(trim($dateStr)));        if(preg_match($checkPattern,$date)){            preg_match("/([-\/.])/",$date,$outer);            $dilimeter = $outer[1];            list($year,$month,$day) = explode($dilimeter,$date);            if(checkdate($month,$day,$year)){                $spsec = time()-mktime(0,0,0,$month,$day,$year);                if($spsec < 0) throw new Exception("date can not be after today!!!");                $spday = floor($spsec/24/60/60);                return $spday;            }            else{                throw new Exception("the date input is not a valid date");            }        }        else{            throw new Exception("the dateStr is wrong formatted!!!");        }    }

Bardo on the first floor

If you leave the validity test blank, the code is too curved. Only one code is required for calculating the number of days:
$ Day = floor (time ()-strtotime ($ date)/86400 );

2 floor liuzhiqiangruc

Bardo wrote:

If you leave the validity test blank, the code is too curved. Only one code is required for calculating the number of days:
$ Day = floor (time ()-strtotime ($ date)/86400 );

Indeed, strtotime is fine. thank you for your advice. :-)

3rd floor liuzhiqiangruc

Liuzhiqiangruc wrote

Bardo wrote:

If you leave the validity test blank, the code is too curved. Only one code is required for calculating the number of days:
$ Day = floor (time ()-strtotime ($ date)/86400 );

Indeed, strtotime is fine. thank you for your advice. :-)

In addition, strtotime supports a wide range of date formats.

4 floor liuzhiqiangruc

Liuzhiqiangruc wrote

Liuzhiqiangruc wrote

Bardo wrote:

If you leave the validity test blank, the code is too curved. Only one code is required for calculating the number of days:
$ Day = floor (time ()-strtotime ($ date)/86400 );

Indeed, strtotime is fine. thank you for your advice. :-)

In addition, strtotime supports a wide range of date formats.

Http://www.php.net/manual/en/datetime.formats.date.php