PHP Cross Merge arrays

An array of array1 = Array (' A ', ' B ', ' C ');

array2 = Array (' 1 ', ' 2 ', ' 3 ');

Hope to achieve results Array3 = Array (' A ', ' 1 ', ' B ', ' 2 ', ' C ', ' 3 '); This effect,

Method One:

1     functionCross_merge_array ($arr 1,$arr 2)2     {3         $arr 1=array_values($arr 1);4         $arr 2=array_values($arr 2);5         $count=Max(Count($arr 1),Count($arr 2));6         $arr=Array();7          for($i= 0;$i<$count;$i++) {8             if($i<Count($arr 1))$arr[] =$arr 1[$i]; Judge to avoid the subscript crossing9             if($i<Count($arr 2))$arr[] =$arr 2[$i]; Judge to avoid the subscript crossingTen         } One         return $arr; A}

Reference: https://segmentfault.com/q/1010000014216293

Method Two:

1 functionCross_merge_array ($arr 1,$arr 2)2 {3      $size=Count($arr 1) >Count($arr) ?Count($arr 1) :Count($arr 2);//the maximum number of elements to take out4      $arr=Array();5       for($i= 0;$i<$count;$i++) {6  　　    if($i<Count($arr 1)) {7               Array_push($arr,$arr 1[$i]);//press the array into the new variable8          }9 Ten          if($i<Count($arr 2)) { One               Array_push($arr,$arr 2[$i]);//press the array into the new variable A          } -      } -      return $arr; the}

Reference: http://www.songlin51.com/archives/832.html

In fact, the principle is the same:

are based on the long length of the Traverse, and then cross into the new array, in the loop you need to determine whether the subscript is out of bounds

PHP Cross Merge arrays