POJ 2121 Inglish-number Translator

Inglish-number Translator

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 4840		Accepted: 1894

Description

In this problem, you'll be given one or more integers in 中文版. Your task is to translate these numbers into their integer representation. The numbers can range from negative 999,999,999 to positive 999,999,999. The following is an exhaustive list of 中文版 words that your program must account for:
negative, Zero, one, three, four, five, six, seven, eight, nine, ten, eleven, twelve, thirteen, fourteen, fifteen , sixteen, seventeen, eighteen, nineteen, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety, Hundred, Thousand, Million

Input

The input consists of several instances. Notes on input:

1. Negative numbers is preceded by the word negative.
   
2. The word "hundred" is not used when "thousand" could be. For example, are written "one thousand five Hundred", not "fifteen hundred".

The input is terminated by a empty line.

Output

The answers is expected to being on separate lines with a newline after each.

Sample Input

Sixnegative Seven hundred twenty Nineone million one hundred Oneeight Hundred fourteen thousand Twenty

Sample Output

6-7291000101814022

Source

CTU Open 2004,uva 486

AC Code:

#include <iostream> #include <algorithm> #include <cstring> #include <cstdio>using namespace    Std;int Main () {string T;    int sum=0,sum2=0;        while (cin>>t) {if (t== "negative") Putchar ('-');        else if (t== "zero") sum+=0;        else if (t== "one") sum+=1;        else if (t== "a") sum+=2;        else if (t== "three") sum+=3;        else if (t== "four") sum+=4;        else if (t== "five") sum+=5;        else if (t== "six") sum+=6;        else if (t== "seven") sum+=7;        else if (t== "eight") sum+=8;        else if (t== "nine") sum+=9;        else if (t== "ten") sum+=10;        else if (t== "eleven") sum+=11;        else if (t== "twelve") sum+=12;        else if (t== "thirteen") sum+=13;        else if (t== "fourteen") sum+=14;        else if (t== "fifteen") sum+=15;        else if (t== "sixteen") sum+=16;        else if (t== "Seventeen") sum+=17;        else if (t== "eighteen") sum+=18;        else if (t== "nineteen") sum+=19;        else if (t== "twenty") sum+=20;   else if (t== "thirty") sum+=30;     else if (t== "forty") sum+=40;        else if (t== "fifty") sum+=50;        else if (t== "sixty") sum+=60;        else if (t== "seventy") sum+=70;        else if (t== "eighty") sum+=80;        else if (t== "Ninety") sum+=90;        else if (t== "hundred") sum*=100;            else if (t== "thousand") {sum2+=sum*1000;        sum=0;            } else if (t== "million") {sum2+=sum*1000000;        sum=0;        } char C;        C=getchar ();            if (c== ' \ n ') {cout<<sum2+sum<< ' \12 ';            sum2=0;        sum=0; }} return 0;}

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POJ 2121 Inglish-number Translator