Poj1083 Moving Tables

Poj1083 Moving Tables

Moving Tables

Time Limit:1000 MS		Memory Limit:10000 K
Total Submissions:26782		Accepted:8962

Description

The famous ACM (Advanced Computer Maker) Company has rented a floor of a building whose shape is in the following figure.

The floor has 200 rooms each on the north side and south side along the corridor. recently the Company made a plan to reform its system. the reform provided des moving a lot of tables between rooms. because the corridor is narrow and all the tables are big, only one table can pass through the corridor. some plan is needed to make the moving efficient. the manager figured out the following plan: Moving A table from a room to another room can be done within 10 minutes. When moving a table from room I to room j, the part of the cZ partition? Http://www.bkjia.com/kf/ware/vc/ "target =" _ blank "class =" keylink "> keys =" http://www.2cto.com/uploadfile/Collfiles/20150204/20150204092916433.gif "alt =" \ ">
For each room, at most one table will be either moved in or moved out. now, the manager seeks out a method to minimize the time to move all the tables. your job is to write a program to solve the manager "s problem.

Input

The input consists of T test cases. the number of test cases) (T is given in the first line of the input file. each test case begins with a line containing an integer N, 1 <= N <= 200, that represents the number of tables to move.
Each of the following N lines contains two positive integers s and t, representing that a table is to move from room number s to room number t each room number appears at most once in the N lines ). from the 3 + N-rd
Line, the remaining test cases are listed in the same manner as abve.

Output

The output shoshould contain the minimum time in minutes to complete the moving, one per line.

Sample Input

3 4 10 20 30 40 50 60 70 80 2 1 3 2 200 3 10 100 20 80 30 50 

Sample Output

102030

Solution: use the room number to separate the corridor. A counter is set for each "sub-corridor". Each time a + 1 is passed, the counter is sorted quickly. The maximum number of times X10 is the answer;

Reference code:

#include 
 
  #include 
  
   #include 
   
    #include using namespace std;int main(){int t,n,a[401],x,y;cin>>t;while (t--){cin>>n;memset(a,0,sizeof(a));for (int i=0;i
    
     >x>>y;if (x>y){int temp=x;x=y;y=temp;}if (x%2!=0)x++;if (y%2!=0)y++;for (int j=x;j<=y;j+=2)a[j]++;}sort(a,a+401);cout<