POJ2105: IP Address

DescriptionSuppose you are reading byte streams from any device, representing IP addresses. your task is to convert a 32 characters long sequence of '1s 'and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. any 8 bits is a valid part of an IP address. to convert Binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are: 27 26 25 24 23 22 21 20 128 64 32 16 8 4 2 1 InputThe input will have a number N (1 <= N <= 9) in its first line representing the number of streams to convert. N lines will follow. outputThe output must have N lines with a doted decimal IP address. A dotted decim Al IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation. sample Input400000000000000000000000000000000 00000011100000001111111111111111 11001011100001001110010110000000 01010000000100000000000000000001 Sample Output0.0.0.03.128.255.255203.132.229.12880.16.0.1 I wiped it. If I use an int array, I never figured out the answer. Using char quickly would be correct. Why? [Cpp] # include <stdio. h> # include <iostream> # include <math. h> using namespace std; int main () {int n; char a [35]; cin> n; getchar (); while (n --) {int I; gets (a); for (I = 0; I <32; I ++) {if (I + 1) % 8 = 0) {int j, sum = 0; for (j = i-7; I-j> = 0; j ++) {if (a [j]! = '0') sum = sum + pow (2.0, (I-j) ;}cout <sum; if (I! = 31) cout <"." ;}} cout <endl ;}return 0 ;}