Python: Array/list (remove () function, append () function, sort () function, reverse () function)

Sort:

1: Finishing Order

 #   bubbling  lista = [5,7,11,19,99,63,3,9,1]list  = []  while  lista!= []: number  = 0  for  i in  Span style= "COLOR: #000000" > lista:  if  number < I:number  = I lista.remove (number) list.append (number)  print  (list)  

  print result: D:\untitled\  1\ Venv\scripts\python.exe d:/untitled/1/venv/main.py[ 99, 63, 19, 11, 9, 7, 5, 3, 1< Span style= "COLOR: #000000" >]process finished with exit code 0   

 #   Select  lista = [5,7,11,19,99,63,3,9,1]list  = []  while  lista!= []:  for  i in   Lista:number = 1 for  J in   lista:  if  number < J:  Number  = J Lista.remove (number) list.append (number)  print  (list)  

Printed results: D:\untitled\1\venv\scripts\python.exe d:/untitled/1/venv/main.py[99, 63, 19, 11, 9, 7, 5, 3, 1 ]process finished with exit code 0

2:sort () function

# sort function lista =[5,7,11,19,99,63,3,9,1]lista.sort ()print(lista)

Printing results:
D:\untitled\1\venv\Scripts\python.exe d:/untitled/1/venv/main.py[1, 3, 5, 7, 9, one, a,,]process Finished with exit code 0

3: Add a number

#if a=18, add this number sequentially in the original listList = [1,4,7,9,11,14,19,34,60,79,98]Print("Previous:%s"%list) a= 18List.append (a) list_1= [] whileList! =[]: number= 100 forIinchlist:ifI <Number:number=I list.remove (number) list_1.append (number)Print("After:%s"%list_1)

Printed results: D:\untitled\1\venv\scripts\python.exe d:/untitled/1/venv/main.py ago: [1, 4, 7, 9, 11, 14, 19, 34, 98]: [1, 4, 7, 9, one, 0,,,, 98]process finished with exit code

Instance:

3*3 table

 #   3*3 table  listx = [1,2,3 for  i in   listx:  for  j in   listx:  if  i >= j:x  = I*j  print  ( "  %s*%s=%s   "% (i,j,x), End="   " )  print  () 

Print Result: D:\untitled\1\venv\scripts\python.exe d:/untitled/1/venv/main.py1*1=1 2*1=2 2*2=4 3*1=3 3*2= 6 3*3=9 Process finished with exit code 0

List Reverse Print: List_num = ["1", "2", "3"] Print order: 3,2,1

Use the Len () function

 #   Reverse list (len () method returns the length of an object (character, list, tuple, and so on) or the number of items  list_num = [ " 1   ", "  2   ", "  3   " ]i  = Len (list_num)  print  (List_num[i-1::-1])  

Printing results:
D:\untitled\1\venv\Scripts\python.exe d:/untitled/1/venv/main.py['3"  2'1']process finished with exit code 0

Use the reverse () function

 list_num = [ " 1   ", "  2   ", "  3   " ]list_num.reverse ()  print  (list_num)  

Print Result: D:\untitled\1\venv\scripts\python.exe d:/untitled/1/venv/main.py['3 ' ' 2 ' ' 1 ' ]process finished with exit code 0

Using the For statement

A = [1,2,3,4,5,6= len (a) for in range (int (NUM/2)):    -i-1] = a[num-i-1 ],a[i]print(a)

D:\untitled\1\venv\Scripts\python.exe d:/untitled/1/venv/main.py[6, 5, 4, 3, 2, 1]process finished With exit code 0

Small knowledge:

List_num = ["1","2","3"]   for in list_num[::-1]:# forward value    print(i)

Print Result: D:\untitled\1\venv\scripts\python.exe d:/untitled/1/venv/main.py321Process Finished with exit code 0

Python: Array/list (remove () function, append () function, sort () function, reverse () function)