Python Development Basics 04-list, tuple, dictionary operation exercises

Source: Internet
Author: User

Exercise 1:

# L1    =  [11,22,33]
# L2 = [22,33,44]
# A. Get a list of elements of the same content
# B. Gets a list of elements in L1 that are not in the L2
# C. Gets a list of elements in L2 that are not in the L1
# d. Get elements with different contents in L1 and L2
# L1    =    [11,22,33]#  L2    =    [22,33,44]# for i in L2:#       If I not in L1:#         Print (i)# for i in L1:#< /c18>     If I not in L2:#         Print (i)
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Exercise 2:

12345678 are combined into a 2-digit number, two-bit values are not repeatable

# Count =0 # For I in range (1, 9): # For      v in range (1, 9):#         If I!=v:#             count + = 1#  # count = count-8#  print (count)
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Exercise 3:

99 Multiplication Table

# For i in range (1,10): #      string = ""#for     J in Range (1,i+1):#         string +=str (j) + "*" +str (i ) + "=" +str (i*j) + "\ T"#     Print (string)
Method 1
# For i in range (1,10): # For      J in Range (1,i+1):#         Print (str (j) + "*" +str (i) + "=" +str (i*j) + "\ T", end= "")  #     print ("\ n", end= "")#  default end=\n#  print (' Alex ', end= ' 11 ')  #  print (' Alex ', ' Haifeng ', ' Gangniang ', sep= ' one ')
Method 2

Exercise 4:

[1,2,3,4] This number two combinations how many kinds of not the same, the number is not repeated

# li = [1,2,3,4] # l =len (LI) # For i in range (0,L-1): # For      v in Range (i+1,l):#         print (li[i],li[v])
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Exercise 5:

Automatic calculation scheme

Hundred Money to buy chickens

Rooster 5 Dollars 1 only, hen a three-piece money, Chicken a penny three. now I have bought 100 chickens with 100 cents,

Ask these 100 chickens, rooster, hen, chicken How many are each?

 for  in range (1,100//5):    is in range (1,100//3):        for   in range (1,100):            if and 5*x + 3*y + Z/3 = =:                print
     (x, Y, z)
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Exercise 6:

Exercise 7:

Exercise 8:

Exercise 9:




Python Development Basics 04-list, tuple, dictionary operation exercise

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