Python PDB debugging method sharing

The code is as follows:

Import PDB

def pdb_test (ARG):
For I in range (ARG):
Print (i)
return arg

Pdb.run ("Pdb_test (3)")

b function name, line number:

Break point, B can query all breakpoints.

The code is as follows:

(Pdb) B pdb_test
Breakpoint 1 at C:\users\plpcc\desktop\pdbtest.py:3
(PDB) b
Num Type Disp Enb Where
Breakpoint Keep Yes at C:\users\plpcc\desktop\pdbtest.py:3

C:

Run the program until a breakpoint is encountered.

The code is as follows:

(PDB) C
> c:\users\plpcc\desktop\pdbtest.py (4) pdb_test ()
-I in Range (ARG):

L

To view the code around a breakpoint

The code is as follows:

(PDB) L
Import PDB

B def pdb_test (ARG):
-I in Range (ARG):
Print (i)
return arg

Pdb.run ("Pdb_test (3)")

A:

View parameters

The code is as follows:

(PDB) A
arg = 3

S, N:

Single-step operation, the difference s will enter the function in the path, n will not enter

P:

View the value of an expression

The code is as follows:

(PDB) P I

Condition

Conditional breakpoint, only if the condition is true breakpoint is hit

The code is as follows:

> c:\users\plpcc\desktop\pdbtest.py (5) pdb_test ()
Print (i)
(PDB) L
Import PDB

def pdb_test (ARG):
For I in range (ARG):
b-> Print (i)
return arg

Pdb.run ("Pdb_test (3)")
[EOF]
(PDB) b
Num Type Disp Enb Where
Breakpoint Keep Yes at C:\users\plpcc\desktop\pdbtest.py:5
(Pdb) Condition 2 i==1//i==1 trigger Breakpoint 2
New condition set for breakpoint 2.
(PDB) b
Num Type Disp Enb Where
Breakpoint Keep Yes at C:\users\plpcc\desktop\pdbtest.py:5
Stop only if i==1
(PDB) C
I==0 Direct Printing not broken
> c:\users\plpcc\desktop\pdbtest.py (5) pdb_test ()
Print (i)//trigger breakpoint, I==1
(PDB) P I

Bt:

Viewing the call stack

The code is as follows:

(PDB) bt
c:\python33\lib\bdb.py (405) Run ()
EXEC (CMD, globals, locals)
(1) ()
> c:\users\plpcc\desktop\pdbtest.py (5) pdb_test ()
Print (i)
R:

Execute to function return

The code is as follows:

(PDB) R

--return--
> c:\users\plpcc\desktop\pdbtest.py (6) pdb_test ()->3//code location, function return value->3
return arg//Code location statement
(PDB) L
Import PDB

def pdb_test (ARG):
For I in range (ARG):
Print (i)
--Return ARG

Pdb.run ("Pdb_test (3)")

Embedding a breakpoint by Pdb.set_trace () at the specified position in the code can usually be controlled by a debug switch

The code is as follows:

Import PDB

__debug__ = True

def pdb_test (ARG):
if True = = __debug__:
Pdb.set_trace ()
For I in range (ARG):
Print (i)
return arg

Pdb_test (3)

Pdb.set_trace () position is broken after run, when __debug__ = False, the code runs correctly

The code is as follows:

> c:\users\plpcc\desktop\pdbtest.py (8) pdb_test ()
-I in Range (ARG):
(PDB) L
__debug__ = True

def pdb_test (ARG):
if True = = __debug__:
Pdb.set_trace ()
-I in Range (ARG):
Print (i)
return arg

Pdb_test (3)
[EOF]

After debugging by PDB.PM (), you can trace the last heap information of the exception program:

The code is as follows:

Traceback (most recent):
File "C:\Users\plpcc\Desktop\pdbTest.py", line +, in
Pdb_test (3)
File "C:\Users\plpcc\Desktop\pdbTest.py", line ten, in Pdb_test
1/0
Zerodivisionerror:division by Zero
>>> Import PDB
>>> pdb.pm ()
> c:\users\plpcc\desktop\pdbtest.py (Ten) Pdb_test ()
1/0
(PDB) L
def pdb_test (ARG):
if True = = __debug__:
Pdb.set_trace ()
For I in range (ARG):
Print (i)
1/0
return arg

Pdb_test (3)

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