Scalar-valued functions

Source: Internet
Author: User
Tags scalar

/*cut the string and get the element based on the index value of the element for example: A,b,c, 2 returns B does not exist return null validation is as follows: If ISNULL (@element, ') = ' print (' not present ')*/ALTER FUNCTION [dbo].[Getelementbyindex](    @text varchar( the),--14123|10| Product Name |    @split_str varchar( -),--|    @index int --2)RETURNS varchar( +) asBEGIN    Set @text=@text+@split_str    Declare @i int=0 --element Position    Declare @element varchar( +)--record the value of an element    Declare @s_index int=1    Declare @e_index int=0    Set @e_index=CHARINDEX(@split_str,@text)     while @e_index>0    begin        Set @element=SUBSTRING(@text,@s_index,@e_index-@s_index)        Set @i=@i+1        if @i=@index return @element        Set @text=SUBSTRING(@text,@e_index+LEN(@split_str),Len(@text)-@e_index)                Set @e_index=CHARINDEX(@split_str,@text)    End     return "'END
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Scalar-valued functions

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