Set Operations,

Set Operations,

Set definition:

• Different Elements
• Unordered
• The element in the set must be of an unchangeable type.

 

Create a set

S = set ("hello") print (s) or s = {1, 2, 3, 3} print (s)

 

 

Set built-in Methods

1. add

# Add element s = {1, 2, 4, 5} s. add ("reese") print (s) # output {1, 2, 3, 4, 5, 'reese '}

 

 

2. clear

# Clear s = {1, 2, 4, 5} s. clear () print (s) # output result: set ()

 

 

3. pop

# Randomly Delete s = {"re", 3, 4, 5, 6, 8} s. pop () print (s) # output result: {4, 5, 6, 8, 'Re '}

 

 

4. remove (delete. An error is returned if the deleted element does not exist)

# Specify to delete s = {1, 2, 4, 5, 7, "neo"} s. remove ("neo") print (s) # output result: {1, 2, 3, 4, 5, 7}

 

 

5. discard

# Specify the deletion. If the deletion element does not exist, no error will be reported for s1 = {1, 2, 3, 4, 5, 7, "neo"} s1.discard ("neo") print (s1) s2 = {1, 2, 3, 4, 5, 7, "neo"} s2.discard ("neoll") print (s2) # output result: {1, 2, 3, 4, 5, 7} {1, 2, 3, 4, 5, 7, 'neo '}

 

 

6. intersection

S1 = {12, 34, 56,123,890} s2 = {354, 45, 78, 34,123, 90} print (s1 & s2) # print the intersection (s1.intersection (s2 )) # output result: {34,123} {34,123}

 

 

7. union

S1 = {"reese", 123,567, 89} s2 = {123, 89, 45, "neo"} # print (s1 | s2) print (s1.union (s2 )) # output result: {'neo ', 'reese', 45,567, 89,123} {'neo ', 'reese', 45,567, 89,123}

 

 

 

8. difference

S1 = {"reese", 123,567, 89} s2 = {123, 89, 45, "neo"} # difference set print (s1-s2) print (s1.difference (s2 )) # output result: {'reese ', 567} {'reese', 567}

 

 

 

9. effecric_difference

S1 = {"reese", 123,567, 89} s2 = {123, 89, 45, "neo"} # print ("crossover set", s1 ^ s2) print ("crossover set", s1.equalric _ difference (s2) # output result: crossover set {'reese ', 45, 'neo', 567} crossover set {'reese ', 45, 'neo, 567}

 

 

 

10. isdisjoint

S1 = {, 3} s2 = {, 6} s3 = {, 0} print (s1.isdisjoint (s2) print (s1.isdisjoint (s3) # output result: TrueFalse

 

 

11. issubset

S1 = {1, 2, 3} s2 = {1, 2, 3} print (s1.issubset (s2) # s1 is a subset of s2 # output result: True