Sgu 176. Flow construction

Source: Internet
Author: User

Some sides of the net must be full streams to find the minimum feasible stream.

Question: The Upper and Lower Bound minimum streams. For more information, see Zhou Yuan's "A Simple Method for Solving Network Flow Problems in networks with the upper and lower bound traffic". There is also a non-binary method, but there is no strict proof, so I still use binary.

[Cpp]
# Include <stdio. h>
# Include <stdlib. h>
# Include <string. h>
# Include <string>
# Include <queue>
# Include <algorithm>
# Include <vector>
# Include <stack>
# Include <list>
# Include <iostream>
# Include <map>
Using namespace std;
# Define inf 0x3f3f3f
# Deprecision Max 110
Int max (int a, int B)
{
Return a> B? A: B;
}
Int min (int a, int B)
{
Return a <B? A: B;
}
Int dis [Max], gap [Max], pre [Max], cur [Max], p [Max];
// Int d [4] [2] = {0, 1, 0, 0,-1,-1 };
Int in [Max], out [Max], id [Max * Max];
Int n, m, s, t, eid;
Int c [Max * Max];
Struct node
{
Int to, next, c;
} E [2 * Max], ee [2 * Max];
Void addedge (int u, int v, int c)
{
Ee [eid]. to = v;
Ee [eid]. c = c;
Ee [eid]. next = p [u];
P [u] = eid ++;
}
Int ISAP (int st, int ed, int n, int count) // start point, end point, number of vertices
{
Memset (dis, 0, sizeof (dis ));
Memset (gap, 0, sizeof (gap); gap [0] = n;
Memcpy (cur, p, sizeof (p); // memcpy!
Int I, flag, v, u = pre [st] = st, maxflow = 0, aug = inf; // puts ("akk ");
While (dis [st] <n)
{
For (flag = 0, I = cur [u]; I! =-1; I = e [I]. next) // cur [u]
If (e [I]. c & dis [u] = dis [e [I]. to] + 1)
{
Flag = 1;
 
Break;
}
If (flag)
{
If (aug> e [I]. c)
Aug = e [I]. c;
V = e [I].;
Pre [v] = u;
Cur [u] = I;
U = v;
If (u = ed)
{
For (u = pre [u]; 1; u = pre [u]) // notice!
{
E [cur [u]. c-= aug;
E [cur [u] ^ 1]. c + = aug;
If (u = st) break;
// Puts ("akkk ");
}
Maxflow + = aug;
Aug = inf;
}
}
Else
{
Int minx = n;
For (I = p [u]; I! =-1; I = e [I]. next)
If (e [I]. c & dis [e [I]. to] <minx)
{
Minx = dis [e [I]. to];
Cur [u] = I;
}
If (-- gap [dis [u] = 0)
Break;
Dis [u] = minx + 1;
Gap [dis [u] ++;
U = pre [u];
}
}
// Printf ("Case % d: \ n % d \ n", count, maxflow );
// Printf ("% d \ n", maxflow );
Return maxflow;
}
Int main ()
{
Int m, n, t, count = 1, sum;
Int u, v, I, j, k, x, y, tp;
While (scanf ("% d", & n, & m )! = EOF)
{
Memset (p,-1, sizeof (p ));
Eid = 0;
Sum = 0;
Memset (in, 0, sizeof (in ));
Memset (out, 0, sizeof (out ));
Memset (id,-1, sizeof (id ));
For (I = 0; I <m; I ++)
{
Scanf ("% d", & u, & v, & c [I], & tp );
If (tp = 1)
{
In [v] + = c [I];
Sum + = c [I];
Out [u] + = c [I];
}
Else
{
Id [I] = eid;
Addedge (u, v, c [I]);
Addedge (v, u, 0 );
}
}
For (I = 1; I <= n; I ++)
{
Addedge (0, I, in [I]);
Addedge (I, 0, 0 );
Addedge (I, n + 1, out [I]);
Addedge (n + 1, I, 0 );
}
Addedge (n, 1, inf );
Addedge (1, n, 0 );
Int l, r, mid;
L = 0; r = inf;
// Printf ("% d \ n", inf); puts ("akkkk ");
 
While (l <= r)
{
Mid = (l + r)> 1;
For (I = 0; I <= eid; I ++) e [I] = ee [I];
E [p [n]. c = mid;
E [p [1]. c = 0;
If (ISAP (0, n + 1, n + 2, count ++) = sum)
R = mid-1;
Else
L = mid + 1;
 
}
// ISAP (0, n * m + 1, n * m + 2, count ++ );
If (l> = inf)
Puts ("Impossible ");
Else
{
For (I = 0; I <= eid; I ++) e [I] = ee [I];
E [p [n]. c = l;
E [p [1]. c = 0;
ISAP (0, n + 1, n + 2, count ++ );
Printf ("% d \ n", l );
For (I = 0; I <m; I ++)
{
If (I = 0)
{
If (id [I] =-1)
Printf ("% d", c [I]);
Else
Printf ("% d", e [id [I] ^ 1]. c );
}
Else
{
If (id [I] =-1)
Printf ("% d", c [I]);
Else
Printf ("% d", e [id [I] ^ 1]. c );
}
}
Puts ("");
}
}
 

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.