Simple file encryption/decryption

This file encryption method is different or way to each byte in the text of the XOR or encryption, the logic is very simple:

File Encryption Code implementation:

</pre><pre name= "code" class= "java" >package ********//<span "color: #33cc00;"

> Own definition </span>;
Import Java.io.File;
Import Java.io.RandomAccessFile;

Import Java.util.Scanner;
		public class Test1 {public static void main (string[] args) {System.out.println ("Input file path:");
		String s = new Scanner (system.in). nextline ();
		File f =new file (s);
			if (!f.isfile ()) {System.out.println ("Please enter the correct file path");
			
		return;
		} System.out.println ("KEY:");
		int key =new Scanner (system.in). Nextint ();
			try {Encrypt (f,key);
		SYSTEM.OUT.PRINTLN ("Encryption/decryption complete");
			catch (Exception e) {System.out.println ("Encryption/decryption failed");
		E.printstacktrace (); } private static void Encrypt (File f, int key) throws exception{/* 1. New Randomaccessfile Object assigned to RAF * 2. Single byte loop read The byte value that is read is assigned to B * 3.b or key, and the result is assigned to B * 4. Position subscript back to previous position seek (Raf.getfilepointer ()-1) * 5. Write byte value b back to file * 6. Close Raf

<span style= "White-space:pre" >		</span> * Using Single-byte access is slower, here in byte array form
		 * *
		
		randomaccessfile RAF =new Randomaccessfile (F, "RW");
		Single byte access
		/*int B;
		while ((B=raf.read ())!=-1) {
			b=b^key;
			Raf.seek (Raf.getfilepointer ()-1);;
			Raf.write (b);
		} *
		//byte array access
		//1024 2048 4096 8192
		byte[] Buff =new];
		int n;//Saves the number of each batch while
		((N=raf.read (Buff))!=-1) {for
			(int i=0;i<n;i++) {
				buff[i] ^= key;
			}
			Raf.seek (Raf.getfilepointer ()-n);
			Raf.write (buff, 0, N);
		}
		
		Raf.close ();
	}