Sort list element size in Python

  #对lt列表里元素从小到大排序 
 
 #一, select Sort by  
 
 LT = [3, 5, 2, 1, 8, 4]  
  #求出lt的长度  
 n = Len (LT)  
  #外层循环确定比较的轮数, X is subscript, lt[x] represents all elements of LT in the outer loop  
 for x in Range (n-1):  
  #内层循环开始比较  
  for y in Range (x+1,n):  
  #lt [x] represents a specific element in the for Y Loop, and Lt [y] represents any one of the LT elements.  
  if Lt[x]>lt[y]:  
  #让lt [x] Compare each element in the LT list to find a small  
  Lt[x],lt[y]=lt[y],lt[x]  
 print (LT) 
 
   #二, sort by bubble sort  

lt = [3, 5, 2, 1, 8, 4]
n= Len (LT)
For x in range (n-1):
   For y in range (n-1-x):
      If LT[Y]>LT[Y+1]:
         Lt[y],lt[y+1]=lt[y+1],lt[y]
Print (LT)

Sort list element size in Python