SQL statement used to determine whether the year of a given date is a leap year
Source: Internet
Author: User
SQL statement used to determine whether a given date is in a leap year -- declare @ datedatetime based on the total number of days of the year; set @ dategetdate () selectcasedatediff (day, dateadd (year, datediff (year, 0, @ date), 0), dateadd (year, 1 + datediff (year, 0, @ date), 0) & nbsp SQL statement used to determine whether the year of a given date is a leap year
-- Judge based on the total number of days of the year
Declare @ date datetime;
Set @ date = getdate ()
Select case datediff (day, dateadd (year, datediff (year, 0, @ date), 0), dateadd (year, 1 + datediff (year, 0, @ date ), 0 ))
When 365 then 'Year' else 'Year' end
-- Judge based on the number of days in February
-- Add two months to the last day of the last year of the date, that is, the last day of the year, January 1, February.
Select case day (dateadd (month, 2, dateadd (year, datediff (year, 0, @ date),-1) when 28 then 'Year' else 'Year' end
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