Struct structure will increase program overhead

Struct structure will increase program overhead

On the one hand, the struct structure can enhance the management of variables and increase the readability of the program, but on the other hand, the structure will also increase the overhead of the program.

See the following code:

struct TEST_S{int a;int b;float c;};int _tmain(int argc, _TCHAR* argv[]){TEST_S ts;int a;int b;int c;ts.a = 100;ts.b = 200;ts.c = 300.f;a = 100;b = 200;c = 300.f;return 0;}

Use disassembly tools,

ts.a = 100;ts.b = 200;ts.c = 300.f;
Assign values to the three variables of the struct. In fact, the assembly code in Debug is:
mov         dword ptr [ts],64h mov         dword ptr [ebp-0Ch],0C8h  movss       xmm0,dword ptr ds:[0BA5858h]  movss       dword ptr [ebp-8],xmm0  
From the assembly code, we can see that in addition to the first variable of the struct, the next variable needs to add an offset based on the header address of the struct, rather than the struct, as shown below:
a = 100;b = 200;c = 300.f;
The Assembly Code is as follows:
mov         dword ptr [a],64h  mov         dword ptr [b],0C8h  mov         dword ptr [c],12Ch 
Obviously, one step of address Subtraction is missing.
However, in the case of Release, the compiler optimizes the program by default. The compiled code Under optimization cannot be viewed, so it cannot identify the actual overhead.