The de-weight of the Python list

#需求: #对列表去重: lis = [2,3,5,3,2,4,8,5,6,7,5] (currently three methods, continuously updated ....) Method of thinking from the https://www.cnblogs.com/nyist-xsk/p/7473236.html, thanks to understand the problem solved after the heavy

Lis = [2,3,5,3,2,4,8,5,6,7,5]#method One: Use the Set () set, which takes advantage of the de-weight of the set () set. The result is a row in ascending order.Lis1 =list (set (LIS))Print(LIS1)#method Two: Use the For loop and not in to determine the list that the method gets to is the same as the previous orderLis2 = [] forIinchlis:ifI not inchlis2:lis2.append (i)Print(LIS2)#method Three: Use the method of GroupBy () in class Itertools the method needs to be sorted first (the result of the final output according to the ordered rules)ImportItertoolslis= [2,3,5,3,2,4,8,5,6,7,5]lis2=[]lis.sort ()#do not set reverse=true default is ascending, setting is descending, this step is requiredLis1 =itertools.groupby (LIS) forKvinchLis1:lis2.append (k)Print(LIS2)#[2, 3, 4, 5, 6, 7, 8] Ascending

#其他方法之后更新

Thanks to the https://www.cnblogs.com/nyist-xsk/p/7473236.html author's ideas to solve the following problems.

#需求: Counts the number of occurrences of an element for lis = [2,3,5,3,2,4,8,5,6,7,5].

Lis = [2,3,5,3,2,4,8,5,6,7,5]# de -lis1 == {} for in Lis1:    # count print(DIC)

#需求如下: Give a list of shopping carts and count the results of the list output

"""
Goods = [{"Name": "Computer", "Price": 1999},
         {"Name": "Logitech Mouse", "Price": 10},
         {"Name": "Yacht", "Price": 20},
         {"Name": "Beauty", "Price": 998},
         {"Name": "Logitech Mouse", "Price": 20},
         {"Name": "Computer", "Price": 1999},
         {"Name": "PC", "Price": 2999}]
#输出结果:
New_goods = [{"Name": "Computer", "Price": 1999, "Count": 2},
         {"Name": "Logitech Mouse", "price": Ten, "Count": 1},
         {"Name": "Logitech Mouse", "price": +, "Count": 1},
         {"Name": "Beauty", "price": 998, "Count": 1},
         {"Name": "Yacht", "price": +, "Count": 1},
         {"Name": "Computer", "Price": 2999, "Count": 1}]
"""

Goods = [{"name":"Computer"," Price": 1999},         {"name":"Logitech Mouse"," Price": 10},         {"name":"Yacht"," Price": 20},         {"name":"Beauty"," Price": 998},         {"name":"Logitech Mouse"," Price": 20},         {"name":"Computer"," Price": 1999},         {"name":"Computer"," Price": 2999}]#first go to the weightNew_goods = [] forGoodinchGoods:ifGood not inchnew_goods:new_goods.append (good)#to Count forNew_goodinchnew_goods:new_good["Count"] =Goods.count (New_good)Print(New_goods)

The de-weight of the Python list