The difference between an array pointer and an array of pointers

Array Pointers: A pointer to an array, pointer to array
Array of pointers: array of pointer, which is used to store pointers to arrays where array elements are pointers
Int ( 2) [6] Array pointer: Represents a pointer to array a element representation: (a) [i] (pointer to one-dimensional array, also row pointer)
Int p[6] Pointer array: Indicates that the elements in array A are all intType, that is, the int pointer element represents: (A[i]) orA[i] ([] precedence is higher than )
Code:
#include <iostream>
using namespace Std;
int main ()
{
int a[4] = {1,2,3,4};
intB[4]; Array of pointers
int c) [4]; Array pointers
c = &a; Let C point to the first address of a
for (int i = 0; i<4; i++)
{
B[i] = &a[i]; The elements of the B array are pointers, that is, the element content is the address
}
cout <<B[1] << Endl; B[1]=&AMP;A[1], which is the address in b[1] (the address is stored in data 2), B[1] is the element content in &a[1], that is, 2
cout << (c) [2] << endl;//can be ( c) as the array name, equivalent to a, (c) [2]=a[2], i.e. 3
return 0;
}
Execution Result:
2
3

Note : When you define an array pointer (c) [i], you must give the pointer an address of c=&a, without assigning a direct value ((c) [I]=a[i]) to the pointing (address), otherwise an error occurs
Tip : You can use an array pointer (*C) as an array name

Array pointers
Int (p) [6] () has a high precedence, stating that P is a pointer to a one-dimensional array of type int, that the length of the array is n, that is, the step of P is N, and the p+1 (p is going to span the length of n integer data)
int a[3][4];
Int (p) [4]; Defines an array pointer to an array with 4 elements
P=a; Assigns the first address of the two-dimensional array A to P, i.e. a[0] or &a[0][0]
p++; After the statement executes, the p=p+1,p crosses line A[0] points to the line a[1]

#include <iostream>
using namespace Std;
int main ()
{
int A[3][4] = {{1,2,3,4},{5,6,7,8},{9,10,11,12}};
Int (p) [4];
p = A;
cout << (p) [0] << Endl;
p++;
cout << (p) [0] << Endl;
cout << ((p) +1) << Endl,//((p) +1) equivalent (p) [1], *p at this time an address

}
Execution Result:
1
5
6

pointer array int p[n]
[] High priority, first combined with p to become an array, and then by the int Description This is an integer pointer array, it consists of n pointers Lexington elements (here to execute p+1 is wrong, so the assignment is wrong: P=a,p is an unpredictable representation, there is only p[0],p[ 1]....p[n-1], they are pointer variables can be used to hold the variable address, so p=a; here P represents the value of the first element of the pointer array, the value of the first address of a
int *p[3]; Represents a one-dimensional array holding three pointer variables, respectively p[0],p[1],p[2]
int a[3][4];
for (i=0;i<3;i++)
P[i]=a[i];

PS: The array pointer is just a pointer variable that occupies the memory space of a pointer, the pointer array is multiple pointer variables, in the form of an array of memory, occupy multiple pointers storage space
An array of pointers to represent the elements of column J of line I in the array:
(P[I]+J) ((p+i) +j) ((P+i)) [j] P[i][j]

The difference between an array pointer and an array of pointers