The miracle of Python throwing an anomaly through lambda

Suppose we need a function that doesn't do anything, just throws an exception (some handler in some systems are doing it), we can write the following code intuitively:

def func():    raise Exception("this is a exception")

In this simple function, we prefer to use lambda to implement, and naturally write down the following code:

lambda :raise  Exception("this is a exception")

But unfortunately this is not possible ~ ~ ~ There will be SyntaxError: invalid syntax errors. For specific reasons, you can see Python Lambda

Here are a few of the available miracle masturbation practices:

Method One

func = lambda: (_ for _ in ()).throw(Exception('this is an exception'))

Method Two

If you don't care what the exception message is:

func = lambda: 1/0

It is not difficult to understand that this function will be thrown ZeroDivisionError . This method actually represents a class, such as can also be written as:

func = lambda : [][0]

This type of implementation is an expression that will throw an exception after the lambda.

Method Three

A very negative way, only for python3.x.

func = lambda : exec('raise(Exception("this is an exception"))')

Method Four:

Not yet read.

# python2.xtype(lambda:0)(type((lambda:0).func_code)(  1,1,1,67,'|\0\0\202\1\0',(),(),('x',),'','',1,''),{})(Exception())

Or

# python3.xtype(lambda: 0)(type((lambda: 0).__code__)(    1,0,1,1,67,b'|\0\202\1\0',(),(),('x',),'','',1,b''),{})(Exception())

Last advice: play can, use with caution!

The miracle of Python throwing an anomaly through lambda