The super function in Python understands

The super () function works according to the two parameters that are passed in:

The class name passed in by the first parameter determines where in the MRO is currently located. MRO (Method Resolution Order);

The current MRO list is determined by self, which is passed in the second argument.

Def super (CLS, inst):    MRO = INST.__CLASS__.MRO () #确定当前MRO列表    return Mro[mro.index (CLS) + 1] #返回下一个类

The following code:

Class A (object):  def name:    print (' name is Xiaoming ')    #super (a,self). Name () class B (object):  def name:    print (' name is Cat ') class C (A, B):  def name:    print (' name is Wang ')    super (C,self) . Name () if __name__ = = ' __main__ ':  c = C ()  print (c.__class__.__mro__)  c.name ()

Execute the above code output: When executing the super () function under Class C, the name function under Class A is actually called. The super () function is commented out in a, so it does not go back to execution. and print out the current MRO list order of C,a,b,object.

(<class ' __main__. C ';, <class ' __main__. A ';, <class ' __main__. B ';, <class ' object ' >) name is Wangname is xiaoming

When we remove the annotations in Class A, we execute the code output: As you can see, after a executes, the name () function in B continues to execute. If there is still a super function in B, it will continue to look up for the name () function in object.

(<class ' __main__. C ';, <class ' __main__. A ';, <class ' __main__. B ';, <class ' object ' >) name is Wangname are Xiaomingname is cat