Method One: Incremental construction method
Understanding recursion has to understand what a function does.
#include <cstdio>voidPrint_subset (intNint*a,intCur//the function of Print_subset is to print a subset of the CUR elements of the collection {0,1,..., n-1}, and the collection to be printed is already stored in the A array{printf ("{ "); for(intI=0; i<cur;i++) printf ("%d", A[i]); printf ("}\n"); intmi=cur?a[cur-1]+1:0;//avoid duplicate printing with dictionary order for(inti=mi;i<n;i++)//enumerate what elements the next one can add{A[cur]=i; Print_subset (N,a,cur+1);//recursively print a subset of cur+1 elements }}intMain () {intN; inta[Ten]={}; scanf ("%d",&N); Print_subset (N,a,0);//initially a subset of 0 elements is stored in a, starting to print recursively return 0;}
Method Two: Bit vector method
Enumeration of each bit or not, the complexity is slightly higher than the method, but better understood, because the output is the same as the whole line of thinking, full n-bit output.
#include <cstdio>inta[Ten];voidPrint_subset (intNint*b,intCur//determine cur or not selected{ if(cur==n)//if you determine the N-bit, print the result{printf ("{ "); for(intI=0; i<n;i++) if(B[i]) printf ("%d", A[i]); printf ("}\n"); } Else{B[cur]=1;//This is an optionalPrint_subset (n,b,cur+1);//recursive next oneb[cur]=0;//This one does not choosePrint_subset (n,b,cur+1);//recursive next one }}intMain () {intN; intb[Ten]={}; scanf ("%d",&N); for(intI=0; i<n;i++) a[i]=i; Print_subset (N,b,0); return 0;}
The disadvantage is that the output is not in dictionary order.
Method 3:2 Binary method
A little thought will find that the two methods are in fact corresponding to the binary system.
#include <cstdio>inta[Ten];voidPrint_subset (intNintb//N-bit collection, B-state printing{printf ("{ "); for(intI=0; i<n;i++) if(b& (1<<i)) printf ("%d", A[i]); printf ("}\n");}voidp_s (intN) { for(intI=0;i< (1<<n); i++) Print_subset (n,i);//Enumerate all States}intMain () {intN; scanf ("%d",&N); for(intI=0; i<n;i++) a[i]=i; p_s (n); return 0;}
The advantage of this method is that the code is simple.
Note: The output order of the above three methods is different.
Three algorithms for enumerating all subsets-"Getting Started with algorithms"