Three ways to start a process in C #

1. Start a child process without waiting for the child process to end view Plaincopy to Clipboardprint?
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   private void Simplerun_click (object sender, System.EventArgs e)
   {System.Diagnostics.Process.Start (@ "C:listfiles.bat");
   }
   private void Simplerun_click (object sender, System.EventArgs e)
   {System.Diagnostics.Process.Start (@ "C:listfiles.bat");
   }
   
   
   2. Start the subprocess, wait for the child process to end, and get the output view Plaincopy to Clipboardprint?
   private void Runsyncandgetresults_click (object sender, System.EventArgs e)
   {
   System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo (@ "C:\listfiles.bat");
   Psi. Redirectstandardoutput = true;
   Psi. WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
   Psi. UseShellExecute = false;
   System.Diagnostics.Process Listfiles;
   Listfiles = System.Diagnostics.Process.Start (PSI);
   System.IO.StreamReader myoutput = listfiles.standardoutput;
   Listfiles.waitforexit (2000);
   
   if (listfiles.hasexited)
   {
   String output = Myoutput.readtoend ();
   This.processResults.Text = output;
   }
   }
   private void Runsyncandgetresults_click (object sender, System.EventArgs e)
   {
   System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo (@ "C:\listfiles.bat");
   Psi. Redirectstandardoutput = true;
   Psi. WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
   Psi. UseShellExecute = false;
   System.Diagnostics.Process Listfiles;
   Listfiles = System.Diagnostics.Process.Start (PSI);
   System.IO.StreamReader myoutput = listfiles.standardoutput;
   Listfiles.waitforexit (2000);
   
   if (listfiles.hasexited)
   {
   String output = Myoutput.readtoend ();
   This.processResults.Text = output;
   }
   }
   
   
   3. Open Urlview plaincopy to clipboardprint using the default browser?
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   private void Launchurl_click (object sender, System.EventArgs e)
   {
   String targeturl = @http://www.duncanmackenzie.net;
   System.Diagnostics.Process.Start (TargetUrl);
   }

   
   

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