One for loop completes 1! + 2! +... + 10 !. C
Main ()
{
LongS =0, N =1;
IntI;
For(I =1; I <=10; I ++)
{
N = N * I;
S = S + N;
}
Printf ("S = % LD \ n", S );
}
Yang Hui triangle. c
Main ()
{
Int A [ 10 ] [ 10 ], X, Y;
For (X = 0 ; X < 10 ; X ++)
For (Y = 0 ; Y < 10 ; Y ++)
A [x] [Y] = 0 ;
For (X = 0 ; X < 10 ; X ++)
A [x] [ 0 ] = 1 ;
For (X = 1 ; X < 10 ; X ++)
For (Y = 1 ; Y < 10 ; Y ++)
{
A [x] [Y] = A [X- 1 ] [Y- 1 ] + A [X- 1 ] [Y];
If (A [x] [Y] = 1 )
Break ;
}
For (X = 0 ; X < 10 ; X ++)
{
For (Y = 0 ; Y < 10 ; Y ++)
{
If (A [x] [Y]! = 0 )
Printf ( " % D " , A [x] [Y]);
}
Printf ( " \ N " );
}
}
Connect two strings. c
# Include " Stdio. h "
Main ()
{
Int I, j = 0 ;
Char Str1 [ 50 ], Str2 [ 20 ];
Scanf ( " % S % s " , Str1, str2 );
For (I = 0 ; Str1 [I]! = ' \ 0 ' ; I ++ );
For (; I ++, J ++)
{
Str1 [I] = str2 [J];
If (Str1 [I] = ' \ 0 ' )
Break ;
}
}
Find leap year. c
Main ()
{
IntA;
Scanf ("% D", & );
If(A %4=0) & (A %100! =0) | (A %400=0))
Printf ("Leap year \ n");
}
Search for daffodils. c
Main ()
{
IntG, S, B, X;
For(X =100; X <1000; X ++)
{
G = x %10;
S = x/10%10;
B = x/100;
If(G * g + S * s + B * B = x)
Printf ("% D \ t", X );
}
}
Buy chicken for RMB. c
main ()
{< br> int X, Y, Z;
for (x = 0 ; x <= 20 ; X ++)
{< br> for (y = 0 ; y <= 34 ; y ++)
{< br> Z = 100 -(x + y );
If ( 5 * x + 3 * Y + z/ 3 =< span style =" color: #800080; "> 100 )
printf ( " \ t rooster % d only \ t hen % d only \ t chicken % d only \ n " , x, y, z);
}< BR >}< br>
}