Upload and display of MVC 4 images, and upload of mvc Images

Upload and display of MVC 4 images, and upload of mvc Images

First, let's take a look at how to upload:

1. view

 

Upload page:

  1: @using (Html.BeginForm("Create", "Achievement", FormMethod.Post, new { enctype = "multipart/form-data" }))
  2: {
  3:      <div class="editor-label">
  4:             @Html.LabelFor(model => model.Pictures)
  5:         </div>
  6:         <div class="editor-field">
  7:             <div><input type="file" name="Image" /></div>
  8:         </div>
  9: ｝

Here we needNote the parameters of the BeginForm method.

2. control

  1:  public ActionResult Create(Achivement achieve, HttpPostedFileBase image)
  2:         {
  3:             try
  4:             {
  5:                 
  6:                 if (image != null && image.ContentLength > 0)
  7:                 {
  8:                     string fileName = DateTime.Now.ToString("yyyyMMdd") + "-" + Path.GetFileName(image.FileName);
  9:                     string filePath = Path.Combine(Server.MapPath("~/Images"), fileName);
 10:                     image.SaveAs(filePath);
 11:                     achieve.Pictures = "~/Images/" + fileName ; 
 12:                 }
 13:                 m_achivementService.Create(achieve);
 14:                 return RedirectToAction("Index");
 15:             }
 16:             catch
 17:             {
 18:                 return View();
 19:             }
 20:         }

Now the image has been uploaded to the Images directory,Note that the path of the image saved in the Pictures field must contain "~".

Now let's take a look at how to display:

1. view

  1: @using (Html.BeginForm("Edit", "Achievement", FormMethod.Post, new { enctype = "multipart/form-data" }))
  2: {
  3:    <div class="editor-label">
  4:             @Html.LabelFor(model => model.Pictures)
  5:         </div>
  6:         <div class="editor-field">
  7:             @*@Html.EditorFor(model => model.Pictures)
  8:             @Html.ValidationMessageFor(model => model.Pictures)*@
  9:             <div><input type="file" name="Image" /></div>
 10:             <div>
 11:                 @if (string.IsNullOrEmpty(Model.Pictures))
 12:                 {
 13:                     @:None
 14:                 }
 15:                 else
 16:                 {
 17:                       
 18:                 }
 19:             </div>
 20:         </div>
 21: ｝

Note that Model. Pictures cannot be written directly in src.@ Url. ContentOtherwise, c:/images/123.pngis displayed. The image cannot be displayed normally.

control：

The same operation as create, Which is omitted here.

How does aspnet mvc4 upload photos in a table?

Hide a form at the bottom of the page, which is not displayed by default. Javascript is used to control display and upload. ajax can return a path after asynchronous upload is submitted.
 
How to upload and display images in spring mvc

You can use components to upload JspSmartUpload. This is a class.
<Form name = "f1" id = "f1" action = "/demo/servlet/UploadServlet" method = "post" enctype = "multipart/form-data">
<Table border = "0">
<Tr>
<Td> User name: </td>
<Td> <input type = "text" name = "username" id = "username"> </td>
</Tr>
<Tr>
<Td> password: </td>
<Td> <input type = "password" name = "password" id = "password"> </td>
</Tr>
<Tr>
<Td> photo: </td>
<Td> <input type = "file" name = "pic" id = "pic"> </td>
</Tr>
<Tr>
<Td> photo: </td>
<Td> <input type = "file" name = "pic2" id = "pic2"> </td>
</Tr>
<Tr>
<Td colspan = "2" align = "center"> <input type = "submit"> </td>
</Tr>
</Table>
</Form>
This is directly submitted to the servlet through a form. You need to configure the servlet in spring. (generally, you do not need to configure the servlet ).
In the preceding JSp page, the following is the code in servlet/action. You know how to use the spring framework (no servlet but action ).

Package com. demo. servlet;

Import java. io. IOException;
Import java. text. SimpleDateFormat;
Import java. uti... the remaining full text>