Use of the channel of Go

Func Count (ch Chan int) {counter++ch <-counterfmt. Println ("Counting")}func main () {CHS: = make ([]chan int, ten) for I: = 0; i <; i++ {chs[i] = make (chan int) go Count (ch S[i])}for index, ch: = Range CHS {FMT. PRINTLN (Index, "", <-ch)}} Output consistent result: COUNTING0 11 102 103 104 105 106 107 108 109 10

The guess is that when the range method reads the channel (CHS), it reads the first one, then reads all the rest, and if the remaining pipe buffer data does not fill n, it blocks

Another option:

Func Count (ch chan int) {ch <-countercounter++fmt. Println ("Counting")} Output consistent result: COUNTING0 01 12 13 14 15 16 17 18 19 1

Use of the channel of Go