Use PHP implementation to prevent users from uploading adult photos or topless _php instances

In this tutorial, we will learn how to prevent users from uploading adult photos or topless pictures in PHP.

I stumbled across a very useful phpclasses.org, developed by Bakr Alsharif, that could help developers detect nude photos of pictures based on skin pixel points.

It analyzes the colors used in different parts of a picture and determines whether they match the color tones of the human skin.

As a result of the analysis, he will return a value reflecting the likelihood that the picture contains nudity.

In addition, he can output the parsed picture, which marks the pixels that use the color of the given colour.

It is currently available to analyze png,gif and JPEG images.

Php
The following shows how to use this PHP class.

Let's start with a nf.php file that contains a nude filter.

Copy Code code as follows:

Include (' nf.php ');

Next, create a new class called ImageFilter, and then put it in a variable called $filter.

Copy Code code as follows:

$filter = new ImageFilter;

Gets the score of the picture and places it in a $score variable.

Copy Code code as follows:

$score = $filter-> getscore ($_files[' img '] [' tmp_name ']);

If the picture score is greater than or equal to 60%, show an (alert) message.

Copy Code code as follows:

if ($score >= 60) {
/*message*/
}

Here are all the PHP code:

Copy Code code as follows:

<?php
/*include the nudity Filter file*/
Include (' nf.php ');
/*create a new class called $filter * *
$filter = new ImageFilter;
/*get the score of the image*/
$score = $filter-> getscore ($_files[' img '] [' tmp_name ']);
/*if the $score variable is set*/
if (Isset ($score)) {
/*if The image contains nudity, display image score and message. Score value if more than 60%, it are considered an adult image.*/
if ($score >= 60) {
echo "Image scored". $score. "%, It seems that you have uploaded a nude the picture."
/*if the image doesn ' t contain nudity*/
else if ($score < 0) {
echo "Congratulations, you have uploaded a non-nude image."
}
}
?>

Markup language
We can upload images using a basic HTML form.

Copy Code code as follows:

<form method= "POST" enctype= "Multipart/form-data" action= "<?php echo $SERVER [' php_self '];? > ">
Upload Image:
<input type= "file" Name= "img" id= "img"/>
<input type= "Submit" value= "Sumit Image"/>
</form>

Summarize
Please remember that PHP is not able to detect all the nude pictures, so it's not completely believable. I hope you think it's a bit of a use.