Use Python to write 1 plus to any number of interactive small programs about range () function refinement

Serious!?????

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A script that uses Python to add a number from 1 to any size (computer feel All) 交互 .

Here I used the range function (I like to call it Python ridge function, because range has "ridge" meaning), this function can have an interesting usage: range (x), the interpreter will list all the integers from 0~x-1, if it is range (y,x), the interpreter will list from y~ All integers of x-1 (x-1 is equivalent to excluding X, it should be understood); There is also a range (y,x,z), and the interpreter will jump Z lists all integers from y~x-1, the default jump spacing is 1, as range (Y,X) is equivalent to range (y,x,1).

Look at the picture should be better understood:

Note In the last sentence, range (11,2) is not equivalent to range (0,11,2). Here Range (11,2) is judged as "from 11~1" of all integers, naturally returning is an empty list, instead of None,none no practical meaning, and empty list has practical meaning.

Step into the chase.

#PlusCal V1.9 (alpha) by:b1ta - 2015/07/17/09:07name = raw_input("Eh,What is your name:")print "Hello," + name + "!"y = 1while y < 2:    a = input("Please enter a number:")    sum = 0    for i in range(1,a+1):        sum += i    print "Nice,1+2+3+..." ,a,"=",sum    y = input("If you want to try it again,Enter number 1,or enter other number to exit:")print name + ",Press your ‘Enter‘ to say Good-bye."exit()#Have fun!

This is a flawed script, I have the parameter of range in the For Loop (1,x+1), can be omitted in the previous 1, just a 0 problem.

The variable is a 不能转换 string, but can be mixed, but be aware that if the integer type must be comma (,). The following error occurs when you use the plus sign

>>> x=1
>>> y="a"
>>> print x+y

Traceback (most recent call last):
File "<pyshell#2>", line 1, in <module>
print x+y
TypeError: unsupported operand type(s) for +: ‘int‘ and ‘str‘

Because integer types cannot be combined with strings.

There are many defects, such as the sixth line while the loop condition can be improved <y/n>, and the corresponding 11th line. The 6th line should include the "re-enter if not given condition (number)" mechanism (try).

while True:   a=None   try:       a=int(input("Please enter a number:"))   except:pass   if type(a)==int:break

If the input is not a number, it will always loop.

The double equals sign is used for detection, such as 1==2 get

False

On line 11th, if you enter a number less than 2, the calculation continues, and if not, jumps out while. There is a flaw here, and when I enter a It also loops. The reason is because the variable here is a, and it is already assigned, so naming a is not desirable, so a is changed to Num. The name is best not casually, unrelated side to the time oneself also can not understand:

name = raw_input("Eh,What is your name:")print "Hello," + name + "!"y = 1while y < 2:    while True:        num=None        try:            num=int(input("Please enter a number:"))        except:pass        if type(num)==int:break    sum = 0    for i in range(1,a+1):        sum += i    print "Nice,1+2+3+..." ,num,"=",sum    y = input("If you want to try it again,Enter number 1,or enter other number to exit:")print name + ",Press your ‘Enter‘ to say Good-bye."exit()

Now the selection of rows 6th and 15th is also judged (whether or not to continue), my method is to enter 1 to continue, and the other numbers to exit. This is good to do, change while the condition is:

while 0<y<2

Finally, modify the exit question, delete the bottom two lines, add:

raw_input("Press your ‘Enter‘ to say Good-bye.")

The exit () is because it kills the interpreter, which can be used to test the difference . For example, sometimes the script ends up with other code, and exit () "kills" the interpreter at this point (killing the process, or shutting down the interpreter).

Final completion:

#PlusCal V3.0 by:b1ta - 2015/07/17/15:06name = raw_input("Eh,What is your name:")print "Hello," + name + "!"y = 1while 0<y<2:    while True:        num=None        try:            num=int(input("Please enter a number:"))        except:pass        if type(num)==int:break    sum = 0    for i in range(1,num+1):        sum += i    print "Nice,1+2+3+..." ,num,"=",sum    y = input("If you want to try it again,Enter number 1,or enter other number to exit:")raw_input("Press your ‘Enter‘ to say Good-bye.")#Have fun!

　　

╮ (￣▽￣ ") ╭

Shameless seeking recommendation: Do you have any interest in this article? (Correct answer: Yes?) (? ? ?)? ）

there! No

x('? ') )? ♥ So click on the lower right side of the recommended bar ... ~\ (≧▽≦)/~It's such a happy decision! x(┳_┳) ...

I will try again ... (?﹏?)

So, to encourage me, what's the recommendation at the bottom right?? (? ? ?)?

Yes, yes !

Use Python to write 1 plus to any number of interactive small programs about range () function refinement