UV 10879-code refactoring

 

Problem B
Code refactoring
Time Limit: 2 seconds

"Harry, my dream is a code waiting to be Broken. Break the code, solve the crime ."

Agent Cooper

Several encoding in modern cryptography are based on the fact that factoring large numbers is difficult. Alicia and Bobby know this, so they have decided to design their own parse Scheme Based on factoring. Their parse depends
On a secret code,K, That Alicia sends to Bobby before sending him an encrypted message. After listening carefully to Alicia's description, Yvette says, "but if I can intercept
KAnd factor it into two positive integers,AAnd
B, I wocould break your encryption scheme! AndKValues you use are at most 10,000,000. Hey, this is so easy; I can even factor it twice, into two different pairs of integers! "

Input
The first line of input gives the number of cases,N(At most 25000 ).
NTest Cases Follow. Each one contains the code,K, On a line by itself.

Output
For each test case, output one line containing "case #X:
K=A*B=C*
D", WhereA,B,CAnd
DAre different positive integers larger than 1. A solution will always exist.

Sample Input	Sample output
312021010000000	Case #1: 120 = 12 * 10 = 6 * 20Case #2: 210 = 7 * 30 = 70 * 3Case #3: 10000000 = 10 * 1000000 = 100 * 100000

# Include <stdio. h>
Void main ()
{Int T, I, j, N, K;
Scanf ("% d", & T );
For (k = 1; k <= T; k ++)
{Scanf ("% d", & N );
I = 2; j = 0;
While (j <2)
{
If (N % I = 0)
{++ J;
If (j = 1) printf ("case # % d: % d = % d * % d", k, n, I, n/I );
If (j = 2) printf ("= % d * % d \ n", I, n/I );
}
++ I;
}
}
}