What does it mean to ask for a regular: $con = Preg_replace ('/shop_rate_list (.)) /s ', ' $ ', $con); solutions
Source: Internet
Author: User
What does it mean to ask for a regular: $con = Preg_replace ('/shop_rate_list\ (. *) \/s ', ' $ ', $con);
Preg_replace ('/shop_rate_list\ (. *) \/s ', ' $ ', $con);
1)
'/shop_rate_list\ ((. *) \)/s '
/with/s
Start and end, plus s is case insensitive.
Shop_rate) list\ (
Because () is a special symbol, the \ (\) conversion is required.
(. *) all content.
2)
' $ ' can be understood as a variable that gets the contents of the 1th occurrence () in the regular.
The 1th time () is the 2nd time, and so on.
So the point is to get shop_rate_list\ ((. *) \), which gets both the contents of the () in the Shop_rate_list ()
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