Zoj 2971 give me the number; zoj 2311 inglish-number Translator (character processing, anti-air line, strstr)

Zoj 2971 give me the number question

Zoj 2311 inglish-number Translator

 

 

// The two questions are similar, and the details are a little different. Because they are not done together, the processing method is a little different-or the previous method is high-end.

 

 

// The AC code of zoj 2971 (using the strstr function ):

# Include <stdio. h> # include <string. h> char C [33] [10] = {"zero", "one", "two", "three", "four", "five", "Six ", "Seven", "eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen ", "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Sixty", "Seventy", "Eighty ", "Ninety", "Hundred", "Thousand", "million", "and"}; char s [200], SSS [200]; int main () {int ne, sum, flag, I, j, ACC, Len; int tt; scanf ("% d", & TT); getchar (); While (TT --) {gets (s); Ne = 1; sum = 0; flag = 0; ACC = 0; Len = strlen (s); While (flag <Len) {While (s [flag] = '') Flag ++; // while (s [flag] = 'and') Flag ++; for (I = 31; i> = 0; I --) {If (strstr (& S [flag], C [I]) = & S [flag]) // locate C [I] in S. If yes, the return position is not found.-1 is returned, that is, false; & obtain the position {if (I <= 20) ACC + = I; else if (I <= 27) ACC + = (I-18) * 10; else if (I = 28) ACC * = 100; else if (I = 29) {sum + = ACC * 1000; ACC = 0 ;}else if (I = 30) {sum + = ACC * 1000000; ACC = 0;} else if (I = 31) Ne =-1; flag + = strlen (C [I]); break ;}}} printf ("% d \ n", (sum + ACC);} return 0 ;}

String converted

 

 

// The AC code of zoj 2311 (pay attention to this question,Anti-DDOS serviceThat is, if a row has no input, nothing should be output ):

// Simulate // convert an English sentence to an Arabic number. # Include <stdio. h> # include <string. h ># include <algorithm> using namespace STD; int main () {int Len, I, J, K, num, sign, ans; char STR [1010], word [20]; char W [33] [20] = {"negative", "zero", "one", "two", "three", "four ", "five", "Six", "Seven", "eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen ", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "ty", "Sixty" "," Seventy "," Eighty "," Ninety "," Hundred "," Thousand "," million "}; while (gets (STR )) {If (strcmp (STR, "") = 0) continue; // air defense line Len = strlen (STR); STR [Len ++] = ''; num = 0; j = 0; Sign = 1; ans = 0; for (I = 0; I <Len; I ++) {If (STR [I]! = '') Word [J ++] = STR [I]; else {word [J ++] = '\ 0'; For (k = 0; k <32; k ++) {If (strcmp (W [K], word) = 0) {If (k = 0) Sign =-1; else if (k> = 1 & K <= 21) num + = K-1; else if (k> = 22 & K <= 28) num + = (K-19) * 10; else if (k = 29) num = num * 100; else if (k = 30) // consider 1000 {ans + = num * 1000; num = 0;} else if (k = 31) // and 1000000 can be {ans + = num * 1000000; num = 0;} break ;}} j = 0 ;}}ans + = num; printf ("% d \ n", ANS * sign);} return 0 ;}

View code