ansible vs chef

Title: http://hzwer.com/3419.htmlTest instructions: Give you a series of all 0, there are m operations [Li,ri], each operation will be subscript in [Li,ri] element inverse. You can choose a number of actions to make the series look different at the end of the sequence.Analysis:It is easy to know that if each operation is not replaced by a combination of other operations, then this operation will contribute to the set of operations, it is possible to have X such an operation, since the ans= opera

-= i i) T + = c[i];returnt;}intMain () {read (n);intBL = (int)sqrt(n +0.5);intS = N/bl + ((n% bl)?1:0); for(inti =1; I for(inti =1; I for(inti =0; I 1]; } for(inti =0; i for(intj =1; J 1]; Sum[i] + =1uLL * Num[i][j] * A[J]; } read (q); while(q--) {intOP, L, R; Read (OP), read (L), read (R);if(OP = =1) { for(inti =0; i 1uLL * Num[i][l] * (R-a[l]); Change (l, R); }Else{--l,--r; LL ans =0;intx = l/bl, y = r/bl;if(x = = y) for(inti = l; I 1);Else{x = (l% BL? x +1: x), y = (R +1)% BL? Y-1:

Two months ago, the process of a workbook, this is not a tutorial not too much to tell the specific painting methods and specific software techniques, mainly when I draw this picture Think of some analysis of the image of the way, so strong software, brush knowledge and basic painting skills need to forgive friends. Effect Chart: 1: At the beginning of the creation I prefer some random graffiti, this sketch is our chef The old man's pro

It means to give you n-course, I need an Ai step to finish the course.How many times do you have to do it at least once each time you can complete one step for M-course?This is definitely not a violent writing, the province last year when the game was not written out of the problem, today, and then the idea of a rationale.First of all, we need to be clear1. N 2. n > M① at this point we are not difficult to find this phenomenon, if sum (A[i]) can be divided by M, then we may just need (sum/m) tim

Main topic:Given two numbers, n,m, find if all factorization of M can be n, the whole word output "Yes", OR "No".Text3120 75128 167 8Output:yesyesnoUntil the greatest common divisor is 1, see if the latter is 1.#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Chef and Prime divisors problem CODE:CHAPD (gcd problem)

user only need to put the phone on one side, according to the voice instructions to do a step-to-step cooking, there is not clear where you can view the picture is being displayed, so as to completely free hands.In addition, for the kitchen small white, as long as the software in advance according to the prompts to prepare the ingredients, and then according to the Voice Command step-by-step, you can easily make a delicious dish. After doing the software a few times, the user is able to remembe

Chef and Prime Divisors Problem code: CHAPD (GCD Problem), divisorschapd Question: Given two numbers, n, m, find if all prime factors of m can be n, the output is "Yes", OR "No ". Text: 3120 75128 167 8Output:YesYesNo Until the maximum number of public appointments is 1, you can check whether the latter is 1. # Include Copyright Disclaimer: This article is an original article by the blogger and cannot be reproduced without the permission of

];intd[1010][100010];intl[100010];intr[100010];intblock[100010];intleft[100010];intright[100010];intMain () {memset (c,0,sizeofc);//Freopen ("Xsy2111.in", "R", stdin);//Freopen ("Xsy2111.out", "w", stdout); intM scanf"%d", n);intI for(i=1; i"%d", a[i]); Add (I,a[i]); } bl= -; M= (N+BL-1)/bl; for(i=1; i-1)/bl; for(i=1; i-1) *BL+1; Right[i]=min (I*bl,n); } for(i=1; i"%d%d", l[i],r[i]); S[block[i]]+=sum (R[i])-sum (L[i]-1); d[block[i]][l[i]]++;if(r[i]+1]--; }intJ for(i=1; i for(j=2; j-1];i

First, the basic introduction==========================================================================================Ansible is a new automated operation tools, based on Python development, the collection of a number of operations tools (puppet, Cfengine, Chef, func, fabric) The advantages of the implementation of batch system configuration, batch program deployment, batch Run command and other functions.

Ansible Introduction Ansible is a new automated operation tools, based on Python development, the collection of a number of operations tools (puppet, Cfengine, Chef, func, fabric) The advantages of the implementation of batch system configuration, batch program deployment, batch Run command and other functions. Ansible