best abstract algebra book

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"Abstract algebra" 02-Algebra and Group

algebraic system of two-dollar operation, referring to the examples are mainly from number theory and permutation transformation. The following discussion will be more verbose in the analysis of ideas, but these are the essence of abstract algebra, and some of the proof process and results are less important. I hope you can always close your books and reconstruct these theories and experience the thinking

[Abstract Algebra] 01-mathematical "Yi tianjian"

essence. I personally think that abstract algebra is a philosophy in mathematics. It is the most valuable thing to constantly think about its nature. It is also of great help to the exercise of abstract thinking and the establishment of scientific methodologies. [Preface] Set Theory, elementary Number Theory [Reference Materials] (continuously updated) [] Mode

Preface to the Advanced Algebra Learning Instruction Book (third edition) of Fudan University

more than 700, the length of the second version of the increase of nearly two-thirds, the book content richer. Finally, on the basis of the second edition, we also add the content that is not involved in the textbook of similar standard type theory, linear mapping and generalized inverse of matrices based on elementary factors in general number field.Different from the general higher algebra problem Sets o

"Abstract algebra" 09-Galois theory

\ (t_k\), the gamma Galois of \ (f (x) \) is not a good analysis. We would prefer \ (y_k\) to be an independent invariant, for which we use the indefinite element \ (X_k\) to establish a polynomial (g (x) \) (Formula (21)), whose coefficient \ (p_k\) is the basic inequality of \ (x_k\) (\ (p_k\) is not an indeterminate element). It is also possible to have the invariant domain of this equation as \ (\bbb{q} (P_1,p_2,\cdots,p_n) \), expanding to \ (\bbb{q} (X_1,x_2,\cdots,x_n) \). It can be argu

Equivalence relation and research object of abstract algebra

1. Abstract algebra is more abstract than that. Of course, as engineering students, our specialty is to use the more tangible things to help understand.First, the object of abstract algebra is primarily a collection, and this set defines some operations (subtraction and the

"Abstract algebra" 05-Rings and Fields

Abstract algebra is not abstract, but the algebraic system studied has a wide range of example prototypes. In the study of group theory, we have seen that many systems have two operations at the same time, and they are interrelated, which forces us to study the structure and characteristics of this algebraic system. On the other hand, the interaction between oper

"Abstract algebra" 03-quotient group and direct product

necessary and sufficient condition to prove its existence is \ (| g_k|\) coprime, the full use of the cycle group has just been discussed proof \ (a\) decomposition of each factor is its generation of the elements of the group, the necessity is through the construction of two \ (p-\) Order (refer to the next article) of the product to export contradictions. In addition, if \ (G=g_1\times g_2\) and \ (G_1\leqslant h\), it is easy to prove that there is \ (H=g_1\times (G_2\cap H) \).\[h= (H\cap g

"Abstract algebra" 06-Ideal with straight and

\), and the conclusion of the proof is the formula (13).\[r/\cap i_k\cong r/i_1\times r/i_2\times\cdots\times r/i_n\tag{13}\]First, easy authentication \ (r\to r/i_1\times r/i_2\times\cdots\times r/i_n\) is the homomorphism mapping, if it can be proved that it is full-shot, by the homomorphism fundamental theorem can be concluded. The proof method is the same as the essence in the elementary number theory, we need to construct for each dimension \ (r_k= (\cdots,0,a_k,0\cdots) \). This condition

"Abstract algebra" 03-quotient group and direct product

necessary and sufficient condition to prove its existence is \ (| g_k|\) coprime, the full use of the cycle group has just been discussed proof \ (a\) decomposition of each factor is its generation of the elements of the group, the necessity is through the construction of two \ (p-\) Order (refer to the next article) of the product to export contradictions. In addition, if \ (G=g_1\times g_2\) and \ (G_1\leqslant h\), it is easy to prove that there is \ (H=g_1\times (G_2\cap H) \).\[h= (H\cap g

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