best book for data structures and algorithms in java

the character before and after the pointer.while (p>s) { *p=*p^*s; *s=*p^*S; *p=*p^*S; p--; s++;} Question 3: How to find the first occurrence of a character in a stringMethod 1: Use the hash table to record the number of occurrences of each character, with the character as the array subscript, and the array size to 256. The first time the scan element will be character statistics, the second pass through to find the first count of 1 characters.Task 4: All subsets of a stringRef

, intersection, and difference operations. So, if you want to perform some normal collection operations on the keys of the collection, you can use the key view objects directly without first converting them to a set.The dictionary's items () method returns an element view object that contains (key, value) pairs. This object also supports collection operations and can be used to find out which two dictionaries have the same key-value pairs.Although the values () method of the dictionary is simila

Tag:prethread Array readinggen thought namelog time Using system;using system.collections.generic;using system.linq;using system.text;using System.Threading.Tasks; Namespace Insert Sort {class Program {static void Main (string[] args) {int[] Arry = {10,3,4,6,7 , 9,8,2,1,0}; Insertsortpro (Arry, 10); for (int i=0;i"Normal insert Sort" is slower than selecting sort, but optimized insert ordering is faster than selecting sort. Insert sort has a feature when the ar

Implementation of the Stack// 栈类function Stack () { this.dataStore = []; this.top = 0; // 栈顶位置 相当于length，不是索引。 this.push = push; this.pop = pop; this.peek = peek; this.clear = clear; this.length = length;}// push: 入栈function push (element) { this.dataStore[this.top++] = element;}// pop: 出栈function pop () { return this.dataStore[--this.top];}// peek: 取栈顶元素function peek () { return this.dataStore[this.top - 1];}// clear: 清空栈function clear () { this.top = 0;}// leng

"Merge Sort" Here we use recursive algorithm to keep the list in two, base case is no element in the list or only one element, because this sub-list is bound to be a positive sequence, and then gradually merge the two sorted sub-list into a new positive sequence table, until all the elements sorted."This is a process from the bottom up (bottom-up)Divides the list from the middle into two sub-lists until it reaches the bottom, with only one element in the sub-list　　Then, the two sub-lists are mer

This is my third side of the question summary.To see the previous content, please visit:http://zhweizhi.blog.51cto.com/10800691/1763237(Some data structure algorithm surface question "One" (update completed))http://zhweizhi.blog.51cto.com/10800691/1775780(Some data structure algorithm surface question "Two" (update completed))http://zhweizhi.blog.51cto.com/10800691/1787562(Some

node without any child nodes.The number of layers in the two-ary tree is L, and the node points are N, then N=2L-1;L=LOG2 (n+1).5. Complete binary TreeConcept: In addition to the last layer, each of the other layers of the number of nodes are full, the last layer if also full, is a full two fork tree, is also a complete binary tree. If the last layer is dissatisfied, the missing nodes are all concentrated on the right, and that is a tree full of two forks.As below, are completely binary tree!!!

judge the case as false. if the match is not modified after the child match ends, it indicates that the match is a full match. The above two methods all use subloops. can we change them to a loop body? In fact, we can see that the primary string will only increase by 1 each time, and the child string will be matched from the beginning each time. so we can change it to a while to control the subscript pointer. Optimization algorithm (2) Function BF_Optimize_2 (sourceStr, searchStr) {var I = 0,

. Ah ah ah ah oh ah ah ah oh ah ah ahThis is not written until 00:00 November 23, 2015.However, in order to maintain the style of unification, or to add a few think well-written blogReport:http://arsenal591.blog.163.com/blog/static/253901269201510169448656Http://www.cnblogs.com/ocNflag/p/4967695.htmlHttp://blog.sina.com.cn/s/blog_1495db3970102w4wl.htmlHttp://www.cnblogs.com/fighter-MaZijun/p/4979318.htmlHttp://www.cnblogs.com/lqf-96/p/lowest-common-ancestor-of-a-binary-tree.htmlRe-attached://The

Linked List of data structures and algorithms Classification of linked lists: (1) single-chain table Header insertion: you only need to maintain one header node, which is often used to simulate the stack; Tail insertion: You need to maintain the head and end nodes, which are often used to simulate queues. (2) Two-way linked list Bidirectional traversal can be use

Array of data structures and algorithms The basic concept of array: array is the simplest and most commonly used data structure, but there are also some considerations: (1) array allocation method and storage location; (2) initialization; (3) Advanced definition of arrays in different languages; (4) multi-dimensional a

The algorithm and data structure, from the very beginning, the realization of dynamic array is first seen.Array.h#include Main.cpp#include "Array.h" int main () {Array arr1 (2); Arr1.printarray (); arr1. InsertAt (1, 1); Arr1.printarray (); arr1. Deleteat (1); Array arr2 (ARR1); Arr2.printarray (); arr1. SetAt (1, 1); Array ARR3 = Arr1;arr3.printarray (); Arr3. Pushback (2); cout Output resultsCome on, that's it.Fundamentals of

the queue, and therefore also called a two-way queue. Write a test program to test the class.Bidirectional Queue class function Deque () {this.datastore = []; This.enqueuefront = Enqueuefront; This.enqueueback = Enqueueback; This.dequeuefront = Dequeuefront; This.dequeueback = Dequeueback; This.front = Front; This.back = back; this.tostring = toString; This.empty = Empty;} Queue-Team first function Enqueuefront (element) {This.dataStore.unshift (element);} Out team-team fir

[low], pivot)) Low++; R[high]= R[low];//move elements that are larger than pivot to the high end} R[low]= pivot;//Set Pivot returnLow//return pivot element position}"Efficiency analysis"Space efficiency: Not sure, worst case is n.Time efficiency: Assuming that the number of elements to be sorted n, then a total of n-1 order, the sub-sequence of j elements to make a trip to the bubble sort needs to be j-1 sub-keyword comparison, bubble sorting time complexity of 0 (n log n).C. Algorithm ex

first 1frequency = [0 forIinchRange (0, 10, 1)] I= 1#do factorial operations, from 1! , 2! , 3! , until 100! The Operation forNinchRange (1, 100, 1): I= n *i m=First_number (i) frequency[m]= Frequency[m] + 1PrintFrequencyResults:/users/liudaoqiang/pycharmprojects/numpy/venv/bin/python/users/liudaoqiang/project/python_project/bat_day17/ 7, 7, 7, 3, ten, 4]process finished with exit code 03. Ben Ford's Law:In life, the probability of the first digit being 1 is nearly 1/3, which is 3 times ti

This is my own written Fibonacci search algorithm, and other ideas on the web slightly different, special posted out:1) There is no pre-stored Fibonacci array, the entire length of the search data can be changed;2) The change of the mid index is dynamic, according to Fibonacci's fallback method;#include #include #define INF 32767#define SIZE 92int Feibinaci (int str[],int n,int key){int F0 = 1;int F1 = 1;int temp;int mid;while (F1 {temp = F1;F1 = F1 +

Linear table Lookup algorithmSequential LookupBinary lookup (linear table must be already sorted)1 /**binary Find2 * @paramobj3 * @paramvalue4 */5 Public Static voidHalfsort (int[] obj,intvalue) {6 intLen=obj.length;//gets the length of the array7 intMin=0;8 intMax=len-2;9 while(minmax) {Ten intMiddle= (Min+max)/2;//gets the subscript for the middle element of an array One if(obj[middle]==value) { ASystem.out.printl

1#include 2#include 3 voidSelectsort (int*a,intn);//pre-declaring the function to be called4 intMainvoid)5 {6 intK;7 intx[Ten]={2,4,6,8,0,1,3,5,7,9};8 for(k=0;kTen; k++)9printf"%d", X[k]);Tenprintf"\ n"); OneSelectsort (x,Ten); A for(k=0;kTen; k++) -printf"%d", X[k]); -printf"\ n"); theSystem"Pause"); - - return 0; - } + - voidSelectsort (int*a,intN//array elements are pointers, number of arrays + { A intI,j,t;//integer variable at intMin//minimum value, inde

1 classTrietree ():2 def __init__(self):3Self.root = {}4 5 defAddNode (SELF,STR):6 #each node (root node) in the tree that contains the number of words to that node, and the key that appears after the node.7Nowdict =Self.root8 forIinchRange (len (str)):9 ifStr[i] not inchNowdict:#discover new ways to combineTenNowdict[str[i]] = {'Count'70A'prefix': str[:i+1]} OneNowdict = Nowdict[str[i]]#move to the next node. Anowdict['Count'] + = 1 - - defCount

One, simple demopublic class Recursion {public static void Main (string[] args) {Test (100);}public static void Test (int n) {if (n = = 0) {Return}SYSTEM.OUT.PRINTLN (n);Test2 (n-1);}}Two, triangle numberpublic class Triangle {public static int GetNumber (int n) {int total= 0;while (n > 0) {Total = Total + N;n--;}return total;}public static int getnumberbyrecursion (int n) {if (n = = 1) {return 1;} else {return n + getnumberbyrecursion (n-1);}}}Test:public class Testtriangle {public static void