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HDU 4268 Alice and Bob (Multiset | Line Segment tree)

Label: acm c Algorithm Alice and Bob Time Limit: 10000/5000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)Total submission (s): 2901 accepted submission (s): 941 Problem descriptionalice and Bob's game never ends. today, they introduce a new game. in this game, both of them have n Different rectangular cards respectively. alice wants to use his cards to cover Bob's. the card a can cover the c

Ultraviolet A 1484 Alice and Bob's Trip (tree dp)

Source: Ultraviolet a HDU QuestionA tree with n nodes numbered 0 ~ N-1, vertex is 0Each edge has a weight.Alice and Bob start at the vertex and go down to the leaf node.For the first time, Bob chooses the child node to go to, and for the second time, Alice takes turns...Each time you walk through an edge, you will get the corresponding weight. Bob wants the larger the total weight of the path, the better, and Ali

HDU 4268 Alice and Bob 37th ACM/ICPC Network Competition 1002 (Greedy + Multiset)

Alice and Bob Time Limit: 10000/5000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)Total submission (s): 627 accepted submission (s): 245 Problem descriptionalice and Bob's game never ends. today, they introduce a new game. in this game, both of them have n Different rectangular cards respectively. alice wants to use his cards to cover Bob's. the card a can cover the card B if the height of A i

HDU 4268 Alice and Bob (set + greedy)

Alice and Bob Time Limit: 10000/5000 MS (Java/others) memory limit: 32768/32768 K (Java/Others) Total submission (s): 1796 accepted submission (s): 641 Problem descriptionalice and Bob's game never ends. today, they introduce a new game. in this game, both of them have n Different rectangular cards respectively. alice wants to use his cards to cover Bob's. the card a can cover the card B if the hei

HDU 4268 Alice and Bob

Alice and Bob's game never ends. today, they introduce a new game. in this game, both of them have n Different rectangular cards respectively. alice wants to use his cards to cover Bob's. the card a can cover the card B if the height of A is not smallerB and the width of A is not smaller than B. As the best programmer, you are asked to compute the maximal number of Bob's cards that

"hdu3544" Alice ' s Game

For a piece of n*m chocolate, Alice can only cut vertically, cut into a*m and b*m, and a+b=n,bob can only be cut into the cross, only into A*n and B*n, and a+b=m.For n*n of this kind of chocolate, who first cut the first knife, directly let the other side has the opportunity to cut two knives, so Alice could not cut this chocolate, can directly ignore this.After a person will try to choose the former one cu

HDU 4122 Alice ' s mooncake shop

Topic Link http://acm.hdu.edu.cn/showproblem.php?pid=4122Test instructions to the effect that Alice opened a moon cake shop, can receive N to make moon cakes orders, and Alice only in the first hour from January 1, 2000 0 o'clock to start the last m hours of moon cakes, and only on the whole pointWhen making moon cakes, and do not take time to do mooncakes, that is, instant can do super many mooncakes, and

2803 Alice Magteroyd

2803 Alice Magteroydtime limit: 4 sspace limit: 8000 KBtitle level: Golden Gold SolvingView Run ResultsTitle DescriptionDescriptionIn Gensokyo, Alice Magteroyd is a magical man who lives in magical forests and specializes inSummon a puppet. One day, her "engine oil", she found her, to defend the fog rain Marisa to Bavalou DemonThe "destruction" of the law library.She has a magic value of N, each summoning a

Ultraviolet A 1484 Alice and Bob's trip (tree DP)

From http://blog.csdn.net/shuangde800 Source: UV HDU Question A tree with N nodes numbered 0 ~ N-1, vertex is 0Each edge has a weight.Alice and Bob start at the vertex and go down to the leaf node.For the first time, Bob chooses the child node to go to, and for the second time, Alice takes turns...Each time you walk through an edge, you will get the corresponding weight. Bob wants the larger the total weight of the path, the better, and

Sha 1500-Alice and Bob (reasoning)

Sha 1500-Alice and Bob (reasoning) Question connection: Ultraviolet A 1500-Alice and Bob In another sequence on the blackboard, you can choose one number minus one for each operation, or merge two numbers. If one number is reduced to one, it is automatically eliminated and cannot be lost by the operator. Solution: the conclusion is that the number greater than 1 can be regarded as an integer s. To eliminate

Codeforces Round #201 (Div. 1)/346A Alice and Bob

#include #includeusing namespacestd;intgcdintAintb) { returnB?GCD (b,a%b): A;}intn[ -+Ten];intMain () {intT,MAXN =0; scanf ("%d",t); for(intI=0; i) {scanf ("%d",N[i]); MAXN=Max (maxn,n[i]); } intHigh=MAXN; for(intI=0; i1; i++) { for(intj=i+1; j) { intTEM =gcd (N[i],n[j]); MAXN=gcd (Maxn,tem); } } intMovestep = HIGH/MAXN-T; if(movestep1) {printf ("alice\n"); } Else{printf ("bob\n"); } return 0;}A set of

Nbut 1114 Alice ' s puppets (sort statistics, water)

Test instructions: To a tree of names, the output by the layer, the same layer by the name of the dictionary sequence output.Idea: First of all to index each person's name, determine which layer, according to the layer loaded into a set, and then the output of the layer automatically ordered.1#include 2 using namespacestd;3vectorSetstring> > Ord;//one set per layer, automatically sorted by dictionary order4mapstring,int> mapp;//used for hashing5 6 intMain ()7 {8 //freopen ("Input.txt", "R",

PS Synthetic production of Alice in Wonderland Dream Scene effect tutorial

For professional later design, the choice of material is very important, to meet your theme, matching your shape, an element of composition to the picture size, color, and placement of the position, elements And the impact of the elements, should be matched properly. Original: Creative Ideas: The idea comes from the movie "Alice in Wonderland" with the same name. The protagonist of the story is an ordinary girl, from the moment she can

ACdream 1112 Alice and Bob (game & amp; prime screening optimization)

ACdream 1112 Alice and Bob (game prime number screening optimization) Question link: Portal Game rules: Once again, you can divide a heap into two heap x = a * B (! = 1 B! = 1) x indicates the number of original heaps, and a and B indicate the number of new heaps. You can also change the number of the original heap to the approximate number y and y of the original heap! = X. The person who made the last operation wins. Analysis: It is also a stone-r

Acdream 1112 Alice and Bob (game && Prime number screening optimization)

Topic Link: PortalGame rules:No time can be divided into two piles x = A*b (a!=1b!=1) x is the number of the original heap, A, B is the number of the new heap.It is also possible to change the number of the original heap to the approximate y of the original heap. Y!=x. The person who made the last operation wins.Analysis:It's also a stone-going game, so we just need to make the whole SG value different or better.Let's consider a bunch of them first. Set the number of this heap is x;So the whole

HDU 4122 Alice's mooncake shop monotone queue optimization DP

Alice ' s mooncake shopTime Limit:20 SecMemory limit:256 MBTopic Connectionhttp://acm.hdu.edu.cn/showproblem.php?pid=4122Description the Mid-Autumn Festival, also known as the Moon Festival or Zhongqiu Festival is a popular harvest Festival CE Lebrated by Chinese people, dating back over 3,000 years to moon worship in China ' s Shang dynasty. The Zhongqiu Festival is held on the 15th day of the eighth month in the Chinese calendar, which are in Septem

HDU 4791 Alice's Print Service (2013 Changsha Live race, two minutes)

Alice ' s Print ServiceTime limit:2000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 1855 Accepted Submission (s): 454Problem Descriptionalice is providing print service, while the pricing doesn ' t seem to be reasonable, so people using her Print Service found some tricks to save money.For example, the price was printing less than pages are cents per page, but when printing wasn't less than pages, You just need-p

HDU 3660 Alice and Bob's trip

Hdu_3660 First, if the path cannot be set to within L or R after the next step reaches a node, then this step cannot be taken. As for how to find these nodes that cannot be taken, you can start from the leaf node. If the path is not within L or R, mark the leaf as-1, it indicates that the node cannot come. For other nodes, if all their children are marked as-1, it should also be marked as-1. In this way, we only need to go along the non-1 point. How can we calculate the maximum possible valu

"Hdoj" 3660 Alice and Bob ' s trip

| | tmpans) theAns =tmp; the } the } - } the the if(ans = =-1) the returnINF;94 returnans; the } the } the 98 classInputreader { About PublicBufferedReader Reader; - PublicStringTokenizer Tokenizer;101 102 PublicInputreader (InputStream stream) {103Reader =NewBufferedReader (NewInputStreamReader (stream), 32768);104Tokenizer =NULL; the }106 107 PublicString Next () {108 while(to

Acdream 1112 Alice and Bob (game && Prime number screening optimization)

Topic Link: PortalGame rules:No time can be divided into two piles x = A*b (a!=1b!=1) x is the number of the original heap, A, B is the number of the new heap.You can also change the number of the original heap to the approximate y,y!=x of the original heap. The person who made the last operation wins.Analysis:It's also a stone-going game, so we just need to make the SG value of all the cases different or better.Let's consider a bunch of them first. Set the number of this heap is x;So all the th

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