e3 1285

Most of the parameters of the Xeon E3 1230 v2 and E3 1230 V3 are the same, such as the core, the number of threads, the main frequency, and so on, but the interface types are different, the former is LGA1150, the latter is LGA1155, which means that they need to match the motherboard chip is not the same, can not Xeon E3 1230 V3 and V2 more than a lot of new tech

Small series found that recently a lot of enthusiastic netizens in the network asked a more representative question: about E3 and i5 processor which is good? E3 and i5 which is good i5 compared with E3 processor In the current high-end mainstream installed, the most choice is i5 and E3 processor, which i5

　　 How is E3 1230v5 worth buying? Why do not now recommend the new six generation E3 V5 become everyone installed use this CPU? Why E3 1230v5 no one to buy? A generation of "God U" rapid fall Historical Review In the early years E3 1230 V2 swept the period, with enough to crush the i5 of the super specif

Intel Kaby Lake this generation although not much change, but each market is still to take care of, notebook first, then desktop, and then the workstation and server, including many players favored Xeon E3-1200 series will also upgrade to the V6 version. E3-1200 V6 's first eight models have been exposed, are four core, 8MB three level cache, of which the low-end two models

For DIY computer game players, for the Xeon E3 processor will not be unfamiliar, the previous E3 by virtue of i5 price, comparable to i7 performance, and is called the high cost of high-end God U. With Intel's six-generation Skylake processors listed, the current six generation e3-1230 V5 and i7 6700k new high-end processors have been listed, but

"Singapore Big Bandwidth Server" special machineCpu:e3-1230v3 8 Thread (CORE)Memory: 8GB DDR3 ECCHDD: 1TB SATA3 6gb/sBandwidth: 100Mbps Unlimited FlowIP number: 5Price: 850 yuan/month (renewal of the same price)Test ip:103.47.209.1 (Domestic average ping: 70ms)Download speed: Http://103.47.209.18/500MB_1.testPresent machine, install the system can be delivered;Order: http://www.yun.ms/order.ms?pid=24 (minus 350 Yuan coupon code: WEB350OFF)other configuration please contact;qq:610000152Tel: 400-0

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The E3 Nintendo has no new handheld (the legendary XDs. hehe) and the pocket of the message, was sprayed very seriously, Sony's FF7 re-Seihan and Shamu 3 is the highlight.and Shamu 3 of the crowdfunding speed is said to record, the player's feelings of victory. The author saw that there were also dozens of players in the country who sponsored the knife. It is said that 2 million dollars is not enough for this development, and this time crowdfunding is

A set of classic cost-effective E3 high-end game installed configuration scheme, as follows. Classic high-end high performance price 6000 yuan to strong E3 play the game a masterpiece configure recommendation Accessory Name brand model reference price processor intel Xeon e3-1231 V3 (hash) ￥1299

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Determine the position of the matchTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 15037 Accepted Submission (s): 6022Problem description has N teams (1Input inputs have several groups, the first behavior in each group is two n (1Output gives a ranking that meets the requirements. There is a space between the queue numbers at the time of the output, and no space after the last.Other Notes: Qualifying rankings may not be unique, at which point

Links:http://acm.hdu.edu.cn/showproblem.php?pid=1285Topology sort template.#include HDU 1285 determining the tournament position (topological sorting)

Topological sort Template Questions#include #include #include #include #include using namespace Std;const int MAXE=250000+10;const int MAXH=500+10;typedef struct EDGE{int to,next;};Edge E[maxe];int head[maxh],in[maxh],n,m,cnt;BOOL Map[maxh][maxh];void init (int num){for (int i=0;i{Head[i]=-1;in[i]=0;for (int j=0;jMap[i][j]=false;}cnt=0;}void Add (int a,int b){E[cnt].to=b;E[cnt].next=head[a];head[a]=cnt++;}int main (){int x,y,sum;while (~SCANF ("%d%d", n,m)){Init (n);for (int i=0;i{scanf ("%d%d",

#defineEach (i,n) (int i=1;iusing namespacestd;inthead[100004],rudu[100004];structnode{intTo,next;} bian[100004];inttop=0;intqueu[100004];voidAddintAintb) {bian[top].to=b; Bian[top].next=Head[a]; Head[a]=top++;}intMain () {intn,m; while(~SCANF ("%d%d",n,m)) {intb; memset (Head,-1,sizeof(head)); memset (Rudu,0,sizeof(Rudu)); for(intI=0; i) {cin>>a>>b; Add (A, b); RUDU[B]++; } intC=0; while(cN) { for(intI=1; i) { if(rudu[i]==0) {Queu[c++]=i; Rudu[i]=-

){ - if(G[u][i]) { - if(vis[i]0)return false; - Else if(!vis[i]!DFS (i)) + return false; - } + } Avis[u]=1; at res.push (u); - return true; - } - - BOOLToposort () { -memset (Vis,0,sizeof(Vis)); in for(intI=1; i){ - if(!Vis[i]) { to if(!dfs (i))return false; + } - } the return true; * } $ Panax Notoginseng intMain () { - while(~SCANF ("%d%d",n,m)) { thememset (G,0,sizeof(G)); +

Topic Links: 1285 peaks and segmentsIdea: Enumerate the factors of n, and then check that each section has a mountain. Use RMQ when checking. Preprocessing time complexity is O (NLOGN), the total complexity is so much.There is a solution to the O (n), but it is not.1#include 2 using namespacestd;3 4std::vectorint>v;5 Const intMAXN = 5e4 + -;6 BOOLs[maxn][ -];7 intN, t;8 voidRMQ () {9 for(intI=1; i -; i++) {Ten for(intj=1; j) { One

Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1285 Multiple methods for Topology Sorting Determine competition rankings Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/others) total submission (s): 12796 accepted submission (s): 5139 Problem description has n teams (1 Other note: the qualified ranking may not be unique. In this case, the team with a small number must be in front of the output. The input data must be corre

HDU 1285 determines the competition ranking (Topology Sorting template) It is easy to understand the meaning of the question. The key is to see the following: the matching ranking may not be unique. At this time, the team with a small number must be in the front; Idea: this is the classic application of topological sorting. You can use the queue to prioritize the queuing of small numbers. Topological sorting:Topological sorting is a sort of directed a

(inti =0; I ){Ten //*m =-1; One for(intj =1; J ){ A if(!Indegree[j]) { -m = j; Break; - } the } -result[k++] = m; indegree[m]--;//delete point; + for(intj =1; J //Delete Edge; - if(Map[m][j]) +--Indegree[j]; A } at for(inti =0; I ){ - if(I! =0) -printf"%d", Result[i]); - Else -printf"%d", Result[i]); - } inprintf"\ n"); - } to intMain () + { - while(~SCANF ("%d%d", n, m)) the { *memse

Determine the position of the match, it is very simple topological sort. The collar matrix representation.#include HDU ACM 1285 determines the tournament position