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Netease game 2016 intern recruitment test questions-jing Ziqi, 2016 Jing ZiqiDescription Solutions Use a three-dimensional array input [] [3] [3] To save the input board status. Use a one-dimensional array result [] to save the outcome of each game and use numbers to represent the outcome. 3 indicates o wins, 12 indic

/wKioL1bgrTCCtVkfAAAaN8zpR-c913.png "title=" 5.PNG " alt= "Wkiol1bgrtcctvkfaaaan8zpr-c913.png"/>Create a scheduled task650) this.width=650; "src=" Http://s2.51cto.com/wyfs02/M02/7D/20/wKiom1bgrFzzJuP7AAAdqD8ZKuo939.png "title=" 4.PNG " alt= "Wkiom1bgrfzzjup7aaadqd8zkuo939.png"/>Perform a scheduled taskStart-scheduledtask-taskname "Latinname"Messages Received650) this.width=650; "src=" Http://s3.51cto.com/wyfs02/M00/7D/20/wKiom1bgs93zp7EEAADAew_N-NM740.png "title=" 3.PNG " alt= "Wkiom1bgs93zp7eea

2016 Netty/mina/java nio video tutorial Java game Server Design TutorialRequired add qq:1225462853, note: Programmer learning VideoOther videos can be requested (Netty NET C + +, etc.)Internet Architect Tutorial: http://blog.csdn.net/pplcheer/article/details/71887910Netty recording time is 2015.11-2016.2 months Netty tutorial for encrypted video!NETTY12 all the courses have been recorded, I believe that thr

] yuan, to make them have the same amount of money, can pass through the bank, charge the fee k% yuan. Ask at most how much money they can have. At the beginning of the question did not understand, collect fees, if I give you x yuan, then I have to pay (1+k) x yuan is not it? And then found that the sample is not too. Later found that I give you x yuan, the bank in the X-yuan buckle k*x, so I give the person can only get (1-k) *x yuan, pit ah, that there is such a fee AH ~~ and then read the sam

cut.Early seedlings first to draw a n*m matrix, each lattice has a certain amount of psychic force (absolute value is not greater than 10, may be negative), each sub-matrix (that is, a matrix contained by the original matrix, at least one element) of the psychic value is the sum of the spirit value of the lattice contained within it. You need to find out the psychic value of the child matrix with the greatest psychic value. For example: N=3, m=4, The matrix is as follows:-2 3 4-11-10 2 44 3 2 1

Online game is the first three hours past the back of five, and then two hours did not do anything, the account password has been forgotten, had to re-write it again;hdu-5868hdu-5869hdu-5870hdu-5871hdu-5872hdu-5873hdu-5874hdu-5875hdu-5876#include 　　hdu-5877#include 　　2016 Dalian Online game

namespacestd;Const intMAXN = 1e6+5;intN, A[MAXN];//rmq-st Algorithm//Efficiency Nlogn//Sany, note the difference between the interval [0, n-1] and [1, N]intma[maxn][ -];voidRMQ () {memset (MA,0,sizeof(MA)); for(inti =0; I 1; ++i) ma[i][0] =i; for(intj =1; (12; ++j) for(inti =0; i+ (111; ++i) {if(a[ma[i][j-1]] > a[ma[i+ (11))][j-1] ]) ma[i][j]= ma[i][j-1]; ElseMa[i][j]= ma[i+ (11))][j-1]; }}intQueryintLtintRT) { intK =0; while((11)) 1) K++; if(A[ma[lt][k]] > a[ma[rt-(11][k]])returnMa[lt][k

/article/details/52496697Code:#include #include#include#include#include#include#include#includestring>#includeSet>#include#include#include#include#include#defineRep (I,m,n) for (i=m;i#defineRSP (It,s) for (Set#defineMoD 1000000007#defineINF 0x3f3f3f3f#defineVI vector#definePB Push_back#defineMP Make_pair#defineFi first#defineSe Second#definell Long Long#definePi ACOs (-1.0)#definePII pair#defineLson L, Mid, rt#defineRson mid+1, R, rtConst intmaxn=1e5+Ten;using namespacestd;ll gcd (ll p,ll q) {re

|1]; for(inti=st[x];i) { while(Al; while(Bl; Pl[i]=al-1, pr[i]=bl-1; if(pl[i]1]) pl[i]=0; if(Pr[i]1)|1]) pr[i]=0; }}inlinevoidRANKPT (intXintp) {V[x]= (p?p-st[x]+1:0); TAG[X]=p;} InlinevoidPushdown (intx) { if(tag[x]0)return; intp=Tag[x]; RANKPT (x1, Pl[p]); Rankpt ((x1)|1, Pr[p]); TAG[X]=-1;}voidUpdateintXintAintBintp) { if(Lreturn;} Pushdown (x); intMid= (a+b) >>1; if(l1, A,mid,pl[p]); if(r>mid) Update ((x1)|1, mid+1, B,pr[p]); V[X]=v[x1]+v[(x1)|1];}voidQueryintXintAintb)

Time: 2016-03-18-09:55:52 Title Number: [2016-03-18][poj][1733][parity game] Question: Given a number of intervals within the range of the number of the and, ask from which sentence start is wrong Analysis: Take the right and check the set Interval lengths up to 1000000000 it is not possible to create an array directly, but only 5,000

Time: 2016-04-16-20:19:26 Saturday Title Number: [2016-04-16][ural][2068][game of Nuts] The main idea: given n heap containing odd number of stones, each time the stone into 4 parts, each request is odd, finally can not divide the loss, ask the last who wins Analysis: Odd number of numbers, as long as it is not 1 will be able to decompose,

. Inputmultiple test cases, process till end of the input. The first line contains a positive integersM, which is the number of groups.TheI-th of the nextMLines begins with a positive integerBi Representing the number of teams in the i-th Group, followed by Bi nonnegative integers representing the score of EA CH Team in this group.Number of test Cases mb[i]Score of each team Outputfor each test case, output M lines. Output ' F ' (without quotes) if the scores in the I-th group must is false,

; } }}intMain () {Get(); for(intI=1; i -; i++) printf ("I:%d%d\n", I,sg[i]); return 0;}Run the code and we'll get the following result:Note that in this tableWe can see that when n is a multiple of 8, the SG (n) =n+1; When (n+1) is a multiple of 8, SG (n) =n-1; otherwise SG (n) =n;So we can tell the difference between the SG value and the winner.#include #include#include#includeusing namespacestd;intMain () {intT; scanf ("%d",t); while(t--) { intN; Long Longx,ans=0; scanf ("%d",N)

2016 Dalian Online gameSummary: Weak explosion, a problem has not been made1006 Football Games HDU 58731, test instructions: Team game, Win +2, lose +0, Ping +1. Give the final score to see if it fits.2, Summary: It seems that there is a theorem to determine this sequence,S?1?? +s?2?? +...+s?i?? ≥i (i−1), for all 1≤i≤n−1S?1?? +s?2?? +...+s?n?? =n (n−1), for I==n#include #include#include#include#include#incl

(ch = =EOF)return-1; } Res= CH-'0'; while(ch = getchar ()) >='0' CH '9') Res= Res *Ten+ (CH-'0'); if(Flag = =1) Res= -Res; returnRes;}/** * Enter a string into str, similar to scanf ("%s", str), which ignores whitespace characters in the buffer. The return value is the length of the input string *, and a return of 1 indicates the end of the input. */intGET_STR (Char*str) { CharC; while((c = GetChar ()) ' ') { if(c = =EOF) { return-1; } } intI =0; while(C >' ') {Str[

+1, cmp);103priority_queueint,vectorint>,cmp1>q;104 the for(i=1; i)106 {107Q.push (i); y=a[i].et;108sum-=a[i].d;109x=q.top (); the while(y-a[x].st>ta !)Q.empty ())111 { thesum+=a[x].d;113Q.pop (); x=q.top (); the } theans=min (ans,sum); the }117printf"%d\n", ans);118 }119 return 0; - }121 /*122 //123 124 // the */View CodeHihocoder 1391 Countries "preprocessing + sorting + heap" (ACM-ICPC International College Student