latitude 2120

HP SiteScope Remote Privilege Escalation Vulnerability (CVE-2015-2120)HP SiteScope Remote Privilege Escalation Vulnerability (CVE-2015-2120) Release date:Updated on:Affected Systems: HP SiteScope 11.3xHP SiteScope 11.2xHP SiteScope 11.1x Description: CVE (CAN) ID: CVE-2015-2120HP SiteScope is a non-agent monitoring software that maintains the availability and performance of its distributed IT infrastr

Tags: acm c Language Algorithm Programming and query set Address: HDU 2120 Although this question does not contain many words, it cannot be understood .. It means to find the maximum number of areas surrounded by walls. This is obviously the number of rings. Then, use and query the set to find the number of rings. The Code is as follows: # Include HDU 2120 ice_cream's world I (query set)

How are these longitude determined? The earth is constantly spinning around its axis (the earth's axis is an imaginary line through both the north and the South Poles and the center of the Earth), and the Earth's waist draws a large circle perpendicular to its axis, so that every point on the circle is equal to the north and South poles, and this circle is called "the equator". At the north and south sides of the equator, many circles parallel to the equator are drawn, that is, "weft rings"; the

2120: Number color time limit:6 Sec Memory limit:259 MBsubmit:3665 solved:1422[Submit] [Status] [Discuss] DescriptionInk bought a set of n color brushes (some of which may be the same color), in a row, you need to answer the ink question. Ink will be like you publish the following command: 1, Q L R represents a number of different colors from the L-brush to the R-branch brush. 2, R P Col replaces the P-branch brush with the color col. Do you

]; }}q[n];structcmeow{intP,v,last;} Cq[n];intP,tim, ans[n];intC[m], now;intL=1, r=0, cur=0; inlinevoidAddintx) {now+= (++c[x]) = =1;} InlinevoidDelintx) {now-= (--c[x]) = =0;} InlinevoidChaintPintv) { if(Lr) Add (v), Del (A[p]); A[P]=v;}voidModui () { for(intI=1; i){ while(Cur, Cha (cq[cur].p, CQ[CUR].V); while(Cur>q[i].tim) Cha (cq[cur].p, cq[cur].last), cur--; while(R, add (A[r]); while(RGT;Q[I].R) del (A[r]), r--; while(L; while(LGT;Q[I].L) l--, add (A[l]); ans[Q[i].id]=Now ;

the Kruskal algorithm to use and check set to determine whether the two sets of two sets are the same,if they belong to the same set and merge them, they form a ring. So, in this case, using the M-bar information to merge the points constantly, determine whether the two points belong to a set, if not, then merge; otherwise, ring number plus one. AC Code:1#include 2#include 3#include 4#include 5#include 6#include 7#include 8#include 9#include Ten#include One#include A#include Set> -#include -

; + } A if(t==0)return 0; the Else returnT (K-1) *block+1)+1; + } - intQuery (intLintR) $ { $ intans=0, I; - if(pos[l]==Pos[r]) - { the for(i=l;iif(last[i]; - }Wuyi Else the { - for(i=l;iif(last[i]; Wu for(I= (pos[r]-1) *block+1; iif(last[i]; - for(i=pos[l]+1; i1; i++) ans+=Find (i,l); About } $ returnans; - } - intMain () - { A intm,i,m,s1,s2; + Charfh[2]; theN=read (); m=read (); -Block= (int) sqrt (n); $Me

Ice_cream ' s World ITime limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 848 Accepted Submission (s): 494Problem Descriptionice_cream ' s world is a rich country, it had many fertile lands. Today, the Queen of Ice_cream wants award land to diligent acmers. So there is some watchtowers is set up, and wall between watchtowers is build, in order to partition the Ice_cream ' s WOR Ld. But what many acmers at most can be awarded by the Queen is a big p

The first time I looked at the time was stunned,,,, is simply too ingenious!!!! I didn't know it before. The number of rings can be judged by!!!!!Think carefully,,, sohappy#include #include #include #include using namespace Std;int pre[10001];int Chushihua (int n){for (int i=0;i}int find (int x){while (X!=pre[x]) x=pre[x];return x;}int main (){int n,m;while (scanf ("%d%d", n,m)!=eof){Chushihua (n);int A, B;int i;int ans=0;for (i=0;i{scanf ("%d%d", a,b);if (Find (a)!=find (b)){Pre[find (a)]=find

Problem-solving ideas: Give the N-point relationship, how many rings, if for point X and Point y, they have a wall, that is, they are connected to themselves, if find (x) =find (y), indicating that their root node is the same, they must be directly or indirectly connected, that is, forming a ringExamples ofA total of 3 ringsIce_cream ' s World ITime limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others) total submission (s): 642 Accepted S Ubmission (s): 371Problem Description

; the } + voidWork () { A intL=1, r=0, now=0; the for(intI=1; i){ + while(Nowr);} - while(Now>q[i].pre) {Change (t[now].pos,t[now].pre,l;} $ while(R1); $ while(LGT;Q[I].L) doit (--l,1); - while(RGT;Q[I].R) {doit (R,0);--R;} - while(L0);++l;} theans[q[i].id]=ans1; - }Wuyi for(intI=1; i){ theprintf"%d\n", Ans[i]); - } Wu } - intMain () { Aboutscanf"%d%d",n,m); $ for(intI=1; i"%d", clo[i]); las[i]=clo[i];} - intx,

for(intI=1; i) + { theb[i]=Last[a[i]]; -last[a[i]]=i; $pos[i]= (I-1)/block+1; the } the for(intI=1; i) the Jian (i); the for(intI=1; i) - { in Charch[5]; the inta1,a2; thescanf"%s%d%d",ch,a1,A2); About if(ch[0]=='Q') theprintf"%d\n", Ask (A1,A2)); the Else the gai (A1,A2); + } - return 0; the}Violent sub-blocks, each point to save a same color with him where, in each block sort, find the time of the end of the violence t

]; * } $ Else{Panax Notoginseng for(inti=l;iif(c[i]; - for(inti=q[bel[r]-1]+1; i) the if(c[i]; + } A for(inti=bel[l]+1; ifind (i,l); the returnans; + } - $ voidChangeintXinty) { $ for(intI=1; i0; -a[x]=y; - for(intI=1; i){ the intt=C[i]; -c[i]=Last[a[i]];Wuyi if(t!=c[i]) reset (bel[i]); thelast[a[i]]=i; - } Wu } - About intMain () { $scanf"%d%d",n,m); - for(intI=1; i"%d",a[i]); - build (); - for(intI=1; i

Topic Connectionhttp://acm.hdu.edu.cn/showproblem.php?pid=2120Ice_cream ' s World idescriptionIce_cream ' s world is a rich country, it has many fertile lands. Today, the Queen of Ice_cream wants award land to diligent acmers. So there is some watchtowers is set up, and wall between watchtowers is build, in order to partition the Ice_cream ' s WOR Ld. But what many acmers at most can be awarded by the Queen is a big problem. One wall-surrounded land must is given to only one acmer and no walls i

Obtain the longitude and latitude of a certain place obtain the corresponding geographical location through the latitude and longitude, get the latitude and longitude Recently, we have to use a latitude and longitude to determine whether the latitude and longitude are locat

Calculate the distance between two points based on the latitude and longitude, and the distance between two points based on the latitude and longitudeCalculate the Distance Based on the longitude and latitude of two points How are these cable cables determined? The earth is constantly rotating around the Earth's axis (the Earth's axis is a path through the north

Source and how to calculate latitude and longitudeHow are these cable cables determined? The earth is constantly rotating around the Earth's axis (the Earth's axis is a path through the north and south poles of the Earth and the Center of the EarthImaginary line), draw a large circle perpendicular to the ground axis in the waist of the earth, so that every point in the circle is equal to the distance between the North and South Poles, this circleIt is

SQL statements: Select Location.* from (select *,round (6378.138*2*asin (sqrt () (Pow () (Sin (36.668530*pi ()/180-px_lat*pi ()/180)/2), 2) +cos (36.668530*pi ()/180) *cos (Px_lat*pi ()/180) * POW (Sin ((117.020359*pi ()/180-px_lon*pi ()/180)/2), 2)) (*1000)) As distance from bsx_training where (px_state = 1) and (type_id! = ") and (((Px_lat >= 27.683290277922) and (px_l At Ignore the above SQL statement first. One by one explanationSQL statements sorted by SQLLon1 Current user longitude lat1 c

Recently, the online search for the "method of calculating distances by latitude and longitude coordinates" reveals that most of the online code is as follows:#define PI 3.14159265static double Rc = 6378137; Equatorial radiusstatic double Rj = 6356725; Polar radiusClass JWD{PublicDouble M_longitude, M_latitude;Double M_radlo, M_radla;Double Ec;Double Ed;PublicJWD (double longitude, double latitude){M_longit

what is geocoding. The Geocoding API is an HTTP form of map service interface for programmers to invoke. The main service for those non-web program calls. For example, C #, C + +, Java, and other development languages can send HTTP requests and receive returned data. Users only need to be in the requested URL string splicing good keywords or latitude and longitude information, you can get the corresponding Baidu