It gives you two latitude and longitude, and calculates the distance between them.
How are these cable cables determined? The earth is constantly rotating around the Earth's axis (the Earth's axis is a path through the north and south poles of the Earth and the Center of the EarthImaginary line), draw a large circle perpendicular to the ground axis in the waist of the earth, so that every point in the circle is equal to the distance between the North
publicclassgeoutil{/** * returns a rectangular range based on latitude and longitude **@ paramlng* Longitude * @param lat* Latitude * @param distance* distance (in meters) * @return [lng1,lat1,lng2,lat2] lower-left corner of the rectangle ( LNG1,LAT1) and upper right Corner (LNG2,LAT2) */publicstatic double[]getrectangle (doublelng,doublelat,longdistance) { floatdelta=111000;if (lng!=0lat!=0) { doublelng
Foreword: When doing iOS project today, need to be positioned to get the name of the current city. Baidu Maps SDK has this function, but in order to not rely on a third party, here I use iOS with the framework corelocation to achieve this requirement. IOS8 out, for positioning needs a little more processing, can be normal positioning, this will be at the end of the article to supplement, in the statement before the part is the default iOS7 processing.
First, we need to import the Corelocation s
#region//latitude and longitude transfer of Mercator
static double m_pi = Math.PI;
Transfer of Mercator by latitude
Longitude (Lon), Latitude (LAT)
Public double[] Lonlat2mercator (double lat, double lon)
{
double[] xy = new DOUBLE[2];
Double x = Lon *20037508.342789/180;
Double y = Math.Log (Math.tan (90+lat) *m_pi/360))/(m_pi/180);
y = y *20037508.34789/180;
Xy
Original source: http://blog.163.com/ezy_dk/blog/static/166651492201221445753585/
Reference Web: A preliminary study of nearby location search
The following is a summary of your own SQL code
Declare @EARTH_RADIUS float
Set @EARTH_RADIUS = 6371000.00-Earth's radius
declare @lat float
declare @lng float
declare @dlng float
declare @dlat float
declare @distance int --distance
set @distance = --300 m C9/>set @lat =xx.xxxxx -This is the central location
set @lng = xxx.xxxx -central
It is now often necessary to provide some information about location based on the location provided by the user. Sometimes you can directly determine the latitude and longitude of the user, sometimes not necessarily determine the user's latitude and longitude information, the user is through the input of some road name, landmark building or store name location, but our database may not be stored in the user
Original link: Calculate distance according to two-point latitude and longitudeHow are these longitude determined? The earth is constantly spinning around its axis (the earth's axis is a center of the north-south poles and the Earth.Imaginary line), in the Earth's waist draw a large circle perpendicular to the axis, so that each point on the circle and the North and south poles of the same distance, this circleIt is called "the equator". At the north
Calculate the distance between two-point latitude and longitude under MySQL(2012-12-25 13:21:09)reproduced
Tags: gossip
Category: PHP
The formula is as follows, unit meters:1th latitude and Longitude: lng1 LAT12nd latitude and Longitude: lng2 lat2Round (6378.138*2*asin (sqrt (POW (LAT1*PI ()/180-lat2*pi ()/180)/2), 2) +cos (Lat
Requirements: The title is actually very clear, the specific point is to use HTTP request Google Weather API, get a standard XML file, the XML file contains the weather data we need, then we are parsing this XML document to get the weather data.
Visit Google weather:
http://www.google.com/ig/api?hl=zh-cnweather=,,, 30670000,104019996
30670000 for Latitude, 104019996 for longitude, this is the above XML in the lat
Java calculates the distance between two GPs coordinate points
1. LAT1 Lung1 represents the latitude and longitude of a point, Lat2 Lung2 the latitude and longitude of B point;
2. The difference between the latitude of A=lat1–lat2 two points b=lung1-lung2 the difference of longitude of two points;
3.6378.137 is the earth radius, the unit is kilometer;
The calcul
Tags: height sel href blank CAS datasheet Select IDT OrderSpecify a latitude and longitude, given a range value, to find out the nearest 5 sets of data within this range around the latitude and longitude.Longitude:116.312785Latitude:39.929875Range: 1 degrees (111 km)Long is the data table longitude fieldLat for data table latitude fieldCenter for data tableThe st
How are these cable cables determined? The earth is constantly rotating around the Earth's axis (the Earth's axis is a hypothetical line through the earth's north and south poles and the Earth's Center), draw a large circle perpendicular to the Earth's axis in the waist, so that every point in the circle is equal to the distance between the north and south poles. This circle is called the "Equator ". On the north and south sides of the Equator, draw many circles parallel to the equator, which ar
from:http://blog.csdn.net/zhuqiuhui/article/details/531803951. Find the azimuth of two latitude and longitude points, P0 (LatA, Lona), P1 (LATB, lonb) (many blogs do not write very well, summarize here) def getdegree (LatA, Lona, LATB, lonb): "" " Args: Point P1 (LatA, Lona) point P2 (LATB, lonb) Returns : bearing between the "GPS points, default:the basis of heading direction is" ""
/** * Calculates whether the point is within the radius of a fixed point * @ October 20, 2016 * @param a longitude 1 known * @param b latitude 1 known * @param x longitude 2 * @param y Latitude 2 * @param radius distance of R radius (m) comparison * @return Object[0] is in the known range*/ Public StaticObject[] Getmanypoint (DoubleADoubleBDoubleXDoubleYDoubleR) {object[] obj=Newobject[2]; DoublePK = th
1, theoretical support: if from the point of need to judge a ray and the number of focus of the polygon is odd, then the point in this polygon, otherwise the point outside this polygon. (Rays cannot intersect with polygon vertices)
2, Programming Ideas:
The idea of the program is to make a horizontal ray (parallel to the x-axis, to the x-axis) from point A to the left to determine whether there is a focus on each side.
DLon1, DLon2, DLAT1, dLat2 represent the longitude and
A recent project used latitude and longitude, according to the latitude and longitude of the map to show the corresponding position
Background implementation code:HTML code:
The code is as follows
Copy Code
Address to query: Query results (latitude and longitude): CSS code:JS Code:
============== Split Line ==============Fr
How are these longitude determined? The earth is constantly spinning around its axis (the earth's axis is a center of the north-south poles and the Earth.Imaginary line), in the Earth's waist draw a large circle perpendicular to the axis, so that each point on the circle and the North and south poles of the same distance, this circleIt is called "the equator". At the north and south sides of the equator, many circles parallel to the equator are drawn, which are the "weft rings", the segments tha
Calculate distance based on two-point latitude and longitudeHow are these longitude determined? The earth is constantly spinning around its axis (the earth's axis is a center of the north-south poles and the Earth.Imaginary line), in the Earth's waist draw a large circle perpendicular to the axis, so that each point on the circle and the North and south poles of the same distance, this circleIt is called "the equator". At the north and south sides of
The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion;
products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the
content of the page makes you feel confusing, please write us an email, we will handle the problem
within 5 days after receiving your email.
If you find any instances of plagiarism from the community, please send an email to:
info-contact@alibabacloud.com
and provide relevant evidence. A staff member will contact you within 5 working days.