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DescriptionBessie noted that although humans has many universities they can attend, cows has none. To remedy this problem, she and her fellow cows formed a new university called the University of Wisconsin-farmside, "Moo U "For short."Wishing to admit dumber-than-average cows, the founders created an incredibly precise admission exam called the Cow Sc Holastic Aptitude Test (CSAT) that yields scores in the range 1..2,000,000,000.

Moo University-financial aid Question: A student in a private school applies for a scholarship, and the amount of the school is limited. Therefore, the school wants to select n logarithm from C if the amount does not exceed f. Three numbers N, C, and F are given. Returns the N logarithm in the C logarithm. Each logarithm represents the score and the applied amount respectively. If the total amount in the N logarithm is not greater than F, the interme

Moo university-financial AidTest instructionsA private school student has to apply for a scholarship, but the amount is limited. Therefore, the school would like to select N logarithm from c if the amount does not exceed F.Give three number n,c,f. Represents the n logarithm to be obtained in the C logarithm respectively.Each logarithm represents the score, with the amount of the application. Requires that the total amount of n logarithm not exceed F i

First Direct O (n²) violence. The result is a ... How weak is the usaco data = =First sort, and then you can think of a few yy ... specifically see Code-----------------------------------------------------------------------------------------#include #include #include #include #define REP (i, n) for (int i = 0; i #define CLR (x, C) memset (x, C, sizeof (x))using namespace std;const INT MAXN = 10000 + 5;int h[MAXN];int main () {//freopen ("test.in", "R", stdin);int n;cin >> N;Rep (i, N)scanf ("%d"

Enumeration median + priority Queue Pre-preprocessing X number of n minimum and#include #include#include#include#include#include#includeusing namespaceStd;typedefLong LongLL;Const intmaxn=100000+Ten;intN,c; LL F;structx{LL S; LL v;} T[MAXN];p riority_queueP; LL DP1[MAXN],DP2[MAXN];BOOLcmpConstXa,Constxb) { returna.sB.S;}intMain () {scanf ("%d%d%lld",n,c,f); for(intI=1; i"%lld%lld",t[i].s,t[i].v); Sort (T+1, t+1+c,cmp); LL ans=-1; if(c>=N) {if(n==1) { for(intI=1; iif(t[i].v

rectangle, and then sweep through the time of N.#include #includeusing namespacestd;Const intn=205;CharA[n][n];intN,m,i,j,k,x,y,ans,b[n][n];intMain () {scanf ("%d%d",n,m); for(i=1; i) scanf ("%s", a[i]+1); for(j=1; j) for(i=1; i) if(a[i][j]=='X') b[i][j]=b[i-1][j]+1;Elseb[i][j]=b[i-1][j]; for(i=1; i) for(j=i;j) {x=0; y=0; for(k=1; k) if(b[j][k]-b[i-1][k]==0) {x=Max (x,k); Y=x; while(x1]=='.'a[j][x+1]=='.') {x++; if(b[j][x]-b[i-1][x]==0) y=x; } ans=max (ans, (j-i+1)

0,17,16,20,19. There is breeds of cows; The first Moos at a volume of 5, and the other at a volume of 7.There is 2 cows of breed #1 and 1 cow of breed #2 in Fiel D 2, and there isAnother cow of breed #1 in field 4."Analysis" by test instructions know, each area of the sound size in addition to itself only by the previous region, minus the impact of the previous area, only the sound of their own production, the minimum number of cattle, is a complete backpack.#include #include#include#include#in

Brain-hole problems. Open the number group to record the left and right portions of each point.As long as the first point and the last point are known, the situation of the remaining points can be deduced from the efficiency of O (n).#include #includestring.h>#include#includeusing namespacestd;Const intmaxn=10000;Long LongL[MAXN],R[MAXN],A[MAXN];intMain () {intN,i; while(~SCANF ("%d",N)) {memset (L,0,sizeof(L)); memset (R,0,sizeof(R)); for(i=0; i"%lld",A[i]); Sort (A,a+N); for(I=n; i>=1; i--)

Question link: http://poj.org/problem? Id = 2231 Ideas: Sort and then derive the formula. Code: # Include Poj_2232 Moo volume

Test instructionsThere is a C with cattle, from which to choose (n-1)/2 head, so that they score the median of the largest and need financial assistance and not more than F.Analysis:The use of heaps of large top stacks maintains minimal and.Code:POJ 2010//sep9#include POJ Moo university-financial Aid Large top heap maintenance min and