nagios contact groups

Check nagios configuration file reports the following error: [Nagios @ 2 etc] $/usr/local/nagios/bin/nagios-v/usr/local/nagios/etc/nagios. cfg Nagios Core 4.0.6 Copyright (c) 2009-pre

The Check nagios configuration file has the following error:[Email protected] etc]$/usr/local/nagios/bin/nagios-v/usr/local/nagios/etc/nagios.cfgNagios Core 4.0.6Copyright (c) 2009-present Nagios Core Development Team and Community ContributorsCopyright (c) 1999-2009 Ethan G

Check Nagios configuration file errors such as the following:[Email protected] etc]$/usr/local/nagios/bin/nagios-v/usr/local/nagios/etc/nagios.cfgNagios Core 4.0.6Copyright (c) 2009-present Nagios Core Development Team and Community ContributorsCopyright (c) 1999-2009 Ethan

Check Nagios configuration file errors such as the following:[Email protected] etc]$/usr/local/nagios/bin/nagios-v/usr/local/nagios/etc/nagios.cfgNagios Core 4.0.6Copyright (c) 2009-present Nagios Core Development Team and Community ContributorsCopyright (c) 1999-2009 Ethan

Problem Solving report POJ2289 Jamie's contact GroupsDescriptionJamie is a very popular girl and have quite a lot of friends, so she's always keeps a very long contact list in her cell Phon E. The contact list have become so long that it often takes a long time for she to browse through the whole list to find a Friend ' s number. As Jamie's best friend and a prog

Jamie ' s Contact Groups Time Limit: 7000MS Memory Limit: 65536K Total Submissions: 6902 Accepted: 2261 DescriptionJamie is a very popular girl and have quite a lot of friends, so she's always keeps a very long contact list in her cell Phon E. The contact

Jamie ' s Contact GroupsTime limit:7000MS Memory Limit:65536KB 64bit IO Format:%i64d %i64u SubmitStatusPracticePOJ 2289description Jamie is a very popular girl and have quite a lot of friends, so she's always keeps a very long contact list in her cell Phon E. The contact list have become so long that it often takes a long time for she to browse through the whole

Jamie's contact groups Time Limit: 15000/7000 MS (Java/others) memory limit: 65535/65535 K (Java/Others)Total submission (s): 225 accepted submission (s): 63 Problem descriptionjamie Is a very popular girl and has quite a lot of friends, so she always Keeps a very long contact list in her cell phone. The contact list

The main topic: Your phone Address book has n contacts, m groups, which, some of the contacts in multiple groups. Your task is to delete some of the contacts in some groups so that each contact is in only one group and the fewest number of people in the group. Find out the number of people in the group with the largest

Sha 1345-Jamie's contact groups Question Link Question: given some people, each person has a group. Now everyone needs to select a group to minimize the maximum number of people in all groups. Train of Thought: The second answer, and then use the maximum flow to determine, the source point to each person to build an edge capacity of 1, each person to their own gr

Test instructions: Jamie has a lot of contacts, but it is not easy to manage, he wants to put these contacts into groups, know that these contacts can be divided into which group, and require each group of contact person to the minimum, that is, there is an integer k, so that each group's contact number is not more than K, ask this k minimum is how much? Title An

])) {Isin[v][j]=T; return 1; } } } } return 0;}BOOLMaxmatch () { for(intI=0; i) isin[i].clear (); for(intI=0; i) {memset (Vis,0,sizeof(VIS)); if(! Find (i))return 0; } return 1;}intMain () {//freopen ("In.txt", "R", stdin); while(~SCANF ("%d%d", n,m) (n+m)) { for(intI=0; i) eg[i].clear (); for(intI=0; i) {scanf ("%s", s); while(SCANF ("%d", x) = =1) {eg[i].push_back (x); if(GetChar () = ='\ n') Break; } } intL=0, r=N; while(lr) {Mid= (l+r) >>1; i

Original title: http://poj.org/problem?id=2289#include POJ 2289--jamie ' s contact Groups two points + max flow

Test instructionsFor n points and M points, an n can correspond to only one m, one m can correspond to multiple n, and each n gives the set of M points that he can correspond to, and m corresponds to the minimum value of n majority.Analysis:Network flow + two points.Code:POJ 2289//sep9#include POJ 2289 Jamie's contact Groups two points + network stream