network expansion card

1834: [Zjoi2010]network Network expansionTime Limit:3 Sec Memory limit:64 MBsubmit:1891 solved:937[Submit] [Status] [Discuss]DescriptionGiven a forward graph, each edge has a capacity of C and an expansion fee of W. The expansion fee here refers to the cost of expanding the capacity by 1. 1, in the case of no

The general purchase of the server has 4 network cards, this time after the installation of the server, configure the IP when it is depressedAs a wave 8560m2 server installed Redhat after the network card display:[Email protected] ~]# ifconfig-aEth0 Link encap:ethernet HWaddr 00:e0:ed:2d:0f:58inet addr:192.168.4.10 bcast:192.168.4.255 mask:255.255.255.0Up broadca

(b[i].z,f-h)); H+=P; B[i].z-=q;b[((I-1)^1)+1].z+=q;d[x]=i; if(h==f)returnh; } if(g[1]==n)returnh; C[G[X]]--; if(!c[g[x]]) g[1]=N; G[X]++;c[g[x]]++;d [x]=L[x]; returnh;}intMain () {registerinti; N=read (); M=read (); k=read (); for(i=1; i) {X[i]=read (); Y[i]=read (); Z[i]=read (); co[i]=read (); inch(X[i],y[i],z[i],0); } for(; g[1]1, INF)); for(i=1; iinch(X[i],y[i],inf,co[i]); inch(n+1,1K0); for(;;) {SPFA (); if(Dis[n]==inf) Break; an+=mi[n]*Dis[n]; for(I=n;i;i=qi[i]) b[ro[i]]

++;}voidInsertintUintVintCintW) {Addedge (u,v,c,w); Addedge (V,u,0,-W);} Queueint>Q;voidMCMF (intx) {Flow=0, cost=0; while(1) {memset (A,0,sizeof(a)); memset (DIS,0x3f,sizeof(DIS)); Q.push (s); Pre[s]=-1;d is[s]=0, a[s]=x?x-flow:inf,inq[s]=1; while(!Q.empty ()) { intu=Q.front (); Q.pop (), Inq[u]=0; for(intI=head[u];~i;i=Edges[i].next) { intv=edges[i].to; if(!xedges[i].cap==inf)Continue; if(dis[v]>dis[u]+edges[i].wedges[i].cap>0) {Dis[v]=dis[u]+EDGES[I].W;

bzoj1834Given a forward graph, each edge has a capacity of C and an expansion fee of W. The expansion fee here refers to the cost of expanding the capacity by 1.Please:1, in the case of no expansion, the maximum flow of 1 to N;2, the maximum flow of 1 to N to increase the minimum required for the expansion of K cost.In

],ans=0, pi=0, W;BOOLmark[t+5],inq[t+5];d equeint>Q;inlinevoidInsintFintTintWintc) {e[++cnt]= (Edge) {t,head[f],w,c}; head[f]=CNT; e[++cnt]= (Edge) {f,head[t],0,-c};head[t]=CNT;}BOOLModlabel () { for(intI=s;iINF; D[t]=0; Q.push_back (T); inq[t]=1; while(!Q.empty ()) { intx=Q.front (); Q.pop_front (); for(intI=head[x];i;i=e[i].next)if(e[i^1].wd[x]+e[i^1].cD[e[i].to]) {D[e[i].to]=d[x]+e[i^1].c; if(!Inq[e[i].to]) {Inq[e[i].to]=1; if(D[e[i].to]0]) Q.push_front (e[i].to); ElseQ.push_back (e[

I've been thinking about life again. T_t,nd Array opened small, has been WA, adjusted for one hours only to find AH!!!!! I always thought my isap wrong t_t, but absolutely right!!!!In fact, the first question is very simple, run once the maximum flow can. The second question is to run the maximum flow of the residual network on each edge of the expansion capacity of OO, the cost of the cost of the side, and

BZOJ1834: [Zjoi2010]network Network expansionDescription given a forward graph, each edge has a capacity of C and an expansion fee of W. The expansion fee here refers to the cost of expanding the capacity by 1. 1, in the case of no expansion, the maximum flow of 1 to N, 2, t

[Problem description] Given a directed graph, each side has a capacity C and A resizing cost W. The expansion cost here refers to the cost required to increase the capacity by 1. 1. Without resizing, the maximum stream from 1 to n is required. 2. The minimum resizing cost is required to increase the maximum stream from 1 to n by K. [Input format] the first line of the network. In input file contains three i

Reference:maximum stream + expense flow. first ask the maximum flow can be. The second question is "minimum cost maximum flow". by test instructions, this question can be translated into the "residual network" on the previous question, expanding the capacity of some edges so that the maximum flow from the new graph is K. so easy: for the side of the remaining traffic, the cost of passing through them is 0. The "Increase in traffic" variable is: to the

DescriptionGiven a forward graph, each edge has a capacity of C and an expansion fee of W. The expansion fee here refers to the cost of expanding the capacity by 1.Please:1, in the case of no expansion, the maximum flow of 1 to N;2, the maximum flow of 1 to N to increase the minimum required for the expansion of K cost

(intI=h[u];i;i=e[i].ne)if(e[i].va>0!le[e[i].to]) {Le[e[i].to]=le[u]+1; Q.push (e[i].to); } }returnLE[T];}intDfsintUintf) {if(!f| | U==T)returnFintus=0; for(intI=h[u];iusif(e[i].va>0le[e[i].to]==le[u]+1) {intT=dfs (E[i].to,min (e[i].va,f-us)); e[i].va-=t; e[i^1].va+=t; us+=t; }if(!us) le[u]=0;returnUS;}intDinic () {intRe=0; while(BFS ())) Re+=dfs (S,inf);returnRe;}BOOLSPFA () {queueint>q; for(inti=s;i0; v[s]=0; Q.push (s); while(!q.empty ()) {intU=q.front ()

Implement a two-way NAT virtual network card, nat virtual network cardProblem description and solution are still old problems. NAT configured through iptables in Linux cannot be used in two-way communication environments, you cannot configure a NAT rule to perform NAT on the traffic actively initiated in both directions. There are several solutions to this proble

Case Description: When the actual production environment, the server board is hung, the manufacturer changed a piece of the same model board, the network card is onboard, so the motherboard is equal to the NIC also changed. Then the problem comes and the NIC is all messed up. The NIC does not come up. Now I don't know what the reason is.Analysis Process: Since the motherboard has been changed, but also the

Wireless network card is the device of the terminal wireless networks, which is a wireless terminal equipment which is used on the Internet through the wireless network under the wireless LAN coverage. Wireless card with its compact, easy to carry and so on to win a lot of netizens love. So how does the wireless

Main: First run the maximum flow on the original network, and then add the cost of the side running cost flowHow can you not think of this problem when you are a freshman?Note: MAXN does not necessarily represent the same range of variables#include 　　1834 [Zjoi2010]network Network expansion

Modify network card cache to solve the problem of losing packets on Linux network cardBad packet loss for Linux NICProduction has a Linux device concurrency is relatively large, droped package more, especially when running the game packet, there is a serious loss of packet phenomenon, suspected network

In order to provide high availability of the network we need to set up multiple NIC bindings into a virtual network card to provide services, so as to prevent a piece of network card damage or prevent network cable connection fail

Have a laptop and a desktop , all in the bedroomLaptop can connect to the living room router with wireless card, the desktop computer is not equipped with wireless card, not internetTo pull a cable from the living room router to connect the desktop to the bedroom is obviously stupid, and it's not too economical to buy a relay router in the bedroom.The simplest and most straightforward way to do this is afte

1. Turn off WiFi and call API[DllImport ("Wlanapi.dll"true)] Public Static extern UINT ref Guid Pinterfaceguid, IntPtr preserved);2. Get the current connected WiFi adapter handleThe wlanopenhandle function opens a connection to the server.Just to return Clienthandle, pass in the parameters of Hclienthandle in Wlandisconnect (...).The official explanation is "A handle for the client" and the use of this session. This handle was used by and functions throughout the session. "[DllImport ("Wlanapi.