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[ACM] HDU 5078 Osu!

Label: ACM Osu! Problem descriptionosu! Is a very popular music game. Basically, it is a game about clicking. Some points will appear on the screen at some time, and you have to click them at a correct time. Now, you want to write an algorithm to estimate how diffecult a game is. To simplify the things, in a game consisting of n points, point I will occur at time TI at Place (XI, Yi), And You shoshould click it exactly at TI at (XI, yi ). that mea

HDU 5078 Osu! (2014 ACM Asia semi-finals Anshan I)

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5078 Osu! Time Limit: 2000/1000 MS (Java/others) memory limit: 262144/262144 K (Java/Others)Total submission (s): 180 accepted submission (s): 114Special Judge Problem descriptionosu! Is a very popular music game. Basically, it is a game about clicking. Some points will appear on the screen at some time, and you have to click them at a correct time. Now, you want to write an algorithm

HDU 5003 Osu! (Anshan Network Competition g)

HDU 5003 Osu! Question Link Just sign in and sort the questions and calculate the answers once. Code: #include HDU 5003 Osu! (Anshan Network Competition g)

HDU 5003 Osu! (Mathematics)

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5003 Problem descriptionosu! Is a famous music game that attracts a lot of people. In Osu !, There is a performance scoring system, which evaluates your performance. each song you have played will have a score. and the system will sort all you scores in descending order. after that, the I-th song scored AI will add 0.95 ^ (I-1) * Ai to your total score. Now you are given the task to writ

HDU 5078 Osu! (Anshan site competition)

case, the first line contains an integer N (2 ≤ n ≤1000) denoting the number of the points in the game. then n lines follow, the I-th line consisting of 3 space-separated integers, Ti (0 ≤ Ti Outputfor each test case, output the answer in one line. Your answer will be considered correct if and only if its absolute or relative error is less than 1e-9. Sample Input 252 1 93 7 25 9 06 6 37 6 01011 35 6723 2 2929 58 2230 67 6936 56 9362 42 1167 73 2968 19 2172 37 8482 24 98 Sample output 9.2195444

bzoj-4318:osu!

Descriptionosu is a popular leisure software. We can simplify and adapt the rules of OSU to the following: A total of n operations, each operation only success and failure of the points, the success of the corresponding 1, the failure corresponds to the 0,n operation corresponds to 1 length of 01 strings of N. In this string continuous x 1 can contribute to the score of x^3, this x 1 cannot be included in the other continuous 1 (that is, a very long s

HDU 5078 osu!

Title Link: Hdu 5078 osu!Surface:osu!Time limit:2000/1000 MS (java/others) Memory limit:262144/262144 K (java/others)Total submission (s): 1058 Accepted Submission (s): 550Special Judge Problem descriptionosu! is a very popular music game. Basically, it's a game about clicking. Some points would appear on the screens at Some time, and you had to click them at a correct time. Now, your want to write a algorithm to estimate how diffecult a gam

HDU 5003 Osu! Question 2014 ACM/ICPC Asia Regional Anshan online

Water .. #include HDU 5003 Osu! Question 2014 ACM/ICPC Asia Regional Anshan online

hiho1258 osu! Master

Title Link: http://hihocoder.com/problemset/problem/1258To see the number of combosIdea: water to see how many 1 and s are good1#include 2#include string.h>3#include 4 using namespacestd;5 Charstr[Ten];6 Const intmaxn=10000;7 intMain () {8 intN;9 //freopen ("C:\\users\\acm\\desktop\\2015beijing\\in.txt", "R", stdin);Ten while(SCANF ("%d", n)! =EOF) { One intCnt=0, X; A for(intI=1; i){ -scanf"%s", str); - if(str[0]=='S') cnt++; the Else { -sca

bzoj4318--osu!

1, test instructions: A sequence, a continuous period of 1 pairs of points have 3 Contribution, then ask the desired score2, Analysis: A bare expectation DP, then new to add a 1, the contribution to the answer for x 3 ?(x?1 ) 3 =3 x 2 +3x+1 Direct violence calculates the desired square and expectation, and every time the DP is updated it's fine.#include #include #include #include using namespace STD;#define M 1000010inline intRead () {Charch = getchar (

hdoj-5003-osu!

Problem Descriptionosu! is a famous music game this attracts a lot of people. In osu!, there is a performance scoring system, which evaluates your performance. Each song you has played would has a score. And the system would sort all your scores in descending order. After that, the I-th song scored AI would add 0.95^ (i-1) *ai to your total score. Now is given the task to write a calculator for this system. InputThe first line contains an integer T, d

BZOJ 4318: OSU !, Bzoj4318osu

BZOJ 4318: OSU !, Bzoj4318osuDescriptionosu is a casual software popular with the masses. We can simplify and adapt osu rules to the following: there are a total of n operations, each operation can only be successful or failed, the success corresponds to 1, the Failure Corresponds to 0, n operations correspond to 1 01 string with a length of n. The continuous X 1 in this string can contribute the X ^ 3 scor

bzoj4318 osu!

DescriptionOSU is a popular leisure software. we can simplify and adapt the OSU rules to the following:there are n operations, each operation only success and failure, the success of the corresponding 1, the failure corresponds to the 0,n operation corresponds to 1 length of 01 strings of N. In this string continuous x 1 can contribute to the score of X^3, which x 1 can not be included in the other successive 1 (that is, a very long string of 1, as ex

[Opening] My Osu game programming (OO)

Label: style HTTP Io OS ar SP Div C on Osu is a community-focused music game independently developed and run by Australian Dean Herbert (peppy. The game method is simple, that is1. Circle ): Circle)50. No X is displayed, and the lifecycle is reduced. The 300 and 100 values of the last serial number in the circle are displayed as exciting 300 and drinking 100. 2. Slider. 3. turntable: Press and hold the button to quickly rotate around the center. Bo

LA 7270 osu! Master (statistics)

Test instructions: Given n elements, some have a value, if it is S then is a single, the other is a, the number of increments starting from 1 is how much.Analysis: Then S is separate, to statistics, since it is starting from 1 increments, then the number of statistics 1 can be.The code is as follows:#pragma COMMENT (linker, "/stack:1024000000,1024000000") #include LA 7270 osu! Master (statistics)

luogu1654 osu!

https://www.zybuluo.com/ysner/note/1300315 Problem surfaceThere is a total of \ (n\) operations, each operation only success and failure of the points, the success of the corresponding \ (1\), the failure of the corresponding \ (0\),\ (n\) operation corresponds to \ (1\) A \ (01\) string of length \ (n\) .In this string continuous \ (x\) ( 1\) can contribute to the score of \ (x^3\) , this \ (x\) \ (1\) cannot be other consecutive \ ( 1\) is included.Now give \ (n\), as well as the success rate

"Probability DP" bzoj4318-osu!

operation: why l1[cur]= (l1[1-cur]+1) *a1? In fact, this should be the case: the probability of the current A1 can hit, the resulting expected suffix length (l1[1-cur]+1) *a1① currently has (1-A1) probability can not hit, the resulting expected suffix length 0* (1-a1) ②①+②→l1[cur]= (l1[1-cur) +1) *a1f is the general recursive addition, the current hit probability will not affect f[i-1], and the current probability of the impact of the factors only expected to increase the amount of1#include 2#i

[tsA1490] [2013 China National Training Team second Operation]osu! [Probability dp+ segment tree + matrix multiplication]

+Temp2. S1; - -Matrix T1=TEMP1. S2,t2=Temp2. S2; -A.s2= (Matrix) {t1.a*t2.a,t1.a*t2.b+t1.b,t1.c*t2.a+t2.c,t1.c*t2.b+t1.d+t2.d}; A + returnA; the } - $Node Query (Const intLConst intRConst intNumConst intSConst intt) the { the if(St) the returnTree[num]; the - intmid=l+ (r-l) >>1); in the if(TreturnQuery (l,mid,num1, s,t); the if(S>mid)returnQuery (mid+1,r,num1|1, s,t); About returnCalc (Query (l,mid,num1, s,t), Query (mid+1,r,num1|1, S,t), mid); the } the th

HDU5003 Osu! (Question G of the Anshan division Network Competition in 2014), hdu5003osu

HDU5003 Osu! (Question G of the Anshan division Network Competition in 2014), hdu5003osu 1. Question Description: Click to open the link 2. Problem-Solving ideas: This question is a simple sorting question, which can be calculated based on the meaning of the question. 3. Code: #define _CRT_SECURE_NO_WARNINGS#include Copyright Disclaimer: This article is an original article by the blogger and cannot be reproduced without the permission of the blogg

CF235 Let & amp; #39; s Play Osu! [Dp + probability]

CF235 Let #39; s Play Osu! [Dp + probability] Question: For n positions, the probability pi of O occurrence at each position on 1-n is given. The scoring rules are as follows. x consecutive OSS records are x ^ 2 points, and the sum is calculated. For example, xxoooxooxx scores are as follows: Expected score VcD4KPHA + y7y/vNK7z8KjrM7Sw8fE3LHIvc/authorization + signature + CjxwPsTHw7Q8L3A + cjxwpjxpbwcgc3jjjpq = "http://www.2cto.com/uploadfile/

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