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I have already mentioned in my previous blog that I have used the Chinese Remainder Theorem to find the same equations. This time I have gained some benefits, so I will discuss it in detail.
Before talking about the Chinese residue theorem, let's talk about Euclidean Algorithm and Extended Euclidean Algorithm:
First, the Euclidean algorithm ca
Test instructions: ... I don't have to say it, it seems to be a very tolerant principle, the Chinese remainder theorem .Method: Because the number of N in the topic is 15, using State compression can lift all the combinations, and then open the number of groups, the Chinese remainder theorem, the Chinese
Title Link: BZOJ-3129Problem analysisThe idea of using the partition method, if there are no restrictions, then the program number is C (m-1, n-1).If there is a limitation of Xi >= Ai, then we can subtract the M from Ai-1, which is equivalent to a fixed portion of this part to Xi, which translates into unrestricted conditions.What if there are some restrictions on the XI Consider the allowance: consider which restrictions are violated, that is, what restrictions are XI Then we can find out the a
POJ 1006: Biorhythms Chinese Remainder Theorem
Biorhythms
Time Limit:1000 MS
Memory Limit:10000 K
Total Submissions:121194
Accepted:38157
DescriptionSome people believe that there are three cycles in a person's life that start the day he or she is born. these three cycles are the physical, emotional, and intellectual cycles, and they have periods of lengths 23, 28, and
Related Knowledge points:
1. A ≡ B (modc), A and B are equivalent to a % C = B, that is, a modc = B mod C.
2. If a and B are mutually qualitative (a, B) = 1, obtain the inverse ax 1_1 (modb) of a about model B)
3. Theorem on the remainder:
Theorem 1: If the divisor is an integer multiple of (or minus) the divisor, And the divisor remains unchanged, the
of days from the next same day to the beginningP,e,i,d title in the set!Then you can get three formulas: (num + d)% = = p, (num + d)% = = e; (num + d)% = = i;P,e,i,d is our input, then we need to find Num can, for convenience, we will num+d temporarily as a whole! make x = num + D;namely: x% = = p; x% = = e; x% = = i; xWhat to do? This involves the so-called " Chinese remainder theorem " (The concept of Go
"Theorem Overview"The Chinese remainder theorem (Sun Tzu's theorem) is a method to solve the same-remainder group in ancient China. is an important theorem in number theory. One-element linear congruence Equation group problem was
Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=5446The main topic: C (n, m)% m, where M is the product of different prime numbers, namely M=P1*P2*...*PK, 1≤k≤10.1≤ m≤ n≤10^18. Analysis: If M is a prime number, it can be done directly with the Lucas theorem, but M is not a prime, but a multiplication of prime numbers. so that C (n, m) is x, you can use the Lucas theorem to calculate the X%p1,x%p2, ...
Simple physiological Cycle Simulation
Perform the remainder operation when the value exceeds 23*28*33 (21252.
#include
China Remainder TheoremIf a certain number of X is D1 ,,... The remainder of the DN division is R1, R2 ,... , RN, can be expressed as the following formula:X = r1r1 + r2r2 +... + Rnrn + RdR1 is D2, D3 ,... , DN public multiple, an
contaminated, each method gives an AI, a pi, if the lucky number%pi equals AI will be contaminated, and then give you an interval,Ask how many lucky numbers have not been contaminated in this interval. The problem: This question was first known to be a Chinese residual theorem, and then read a number of problems, found to use the inclusion of the Chinese remainder theo
Introduction of Chinese Residue Theorem
Find a number so that the number is divided into \ (3 \) remainder \ (2 \), \ (5 \) remainder \ (3 \), and \ (7 \) yu \ (2 \).Problem Solving
Next we will solve this problem according to the algorithm process of China's residual theorem and gradually explain its principle.
To sol
next triple peak, In the form:Case 1:the Next triple peak occurs in 1234 days.Use the plural form "days" even if the answer is 1.Sample Input0 0 0 00 0 0 1005 20 34 3254 5 6 7283 102 23 320203 301 203 40-1-1-1-1Sample Outputcase 1:the next triple peak occurs in 21252 days. Case 2:the Next triple peak occurs in 21152 days. Case 3:the Next triple peak occurs in 19575 days. Case 4:the Next triple peak occurs in 16994 days. Case 5:the Next triple peak occurs in 8910 days. Case 6:the Next triple pea
Bell (hdu4767 + matrix + Chinese Remainder Theorem + bell number + Stirling Number + Euclidean), hdu4767stirlingBellTime Limit:3000 MSMemory Limit:32768KB64bit IO Format:% I64d % I64uSubmit Status Practice HDU 4767 DescriptionWhat? MMM is learning Combinatorics !?Looks like she is playing with the bell sequence now:Bell [n] = number of ways to partition of the set {1, 2, 3,..., n}E.g. n = 3:{1, 2, 3}{1} {2
2016.1.26Because more lazy, so first copy Baidu-------------------I'm a split line--------------------In the language of modern mathematics, the Chinese remainder theorem gives the following one-element linear congruence equations: the conditions for the determination of the solution and the concrete form of the solution in the case of the solution by means of the construction method. Chinese
Topic Links:http://acm.hdu.edu.cn/showproblem.php?pid=5768Main Topic :T set of data, the l~r satisfies: 1. is a multiple of 7, 2. The number of%pi!=ai for n primes.Topic Ideas:"Chinese remainder theorem" "Tolerant principle" "fast multiplication" "Number theory" Because they are prime numbers, they are 22 of each other, satisfying the conditions of the Chinese remainder
Ask G's P-%mod,According to the Fermat theorem, G^sigma (c (n,d)) (d|n)%mod=g^ (Sigma (C (n,d)) (d|n)% (mod-1))%mod,However, Mod-1 is not a prime number, it can only be used to split it into 4 mass factors, and then to solve the 4 equations respectively, first with the Lucas theorem and Ma Xiaoding to find out the value of 4 prime numbers of Sigma (Num[i]), notice that the enumeration factor d is enumerated
Chinese remainder theorem, aka grandson Theorem O (* ≧▽≦) MitsujoWhat problems can be solved?Problem:A bunch of things.3 x 3 left 25 x 5 left 37 x 7 left 2Ask how many of this itemTo solve this problem, we need to construct an answerWe need to construct this answer.5*7*INV (5*7, 3)% 3 = 13*7*INV (3*7, 5)% 5 = 13*5*INV (3*5, 7)% 7 = 1These 3 are not correct, don't
#include using namespacestd;intMain () {intP,e,i,d,count=0; while(cin>>p>>e>>i>>d,p!=-1e!=-1i!=-1d!=-1) {Count++; intN= (1288*i+14421*e+5544*p-d+21252)%21252; if(n==0) cout" Case"": The next triple peak occurs in""21252""Days ."Endl; Elsecout" Case"": The next triple peak occurs in""Days ."Endl; } return 0;}Application of the remainder theorem in China (the requirement of application is n%m=r, where m m
23 c*1, that is, more than C.So the conclusion is that 5544*p is divided by 23 and the remainder is divided by 28, divided by 33.14421*e divided by 28 E, divided by 23, divisible by 33, divided by1288*i divided by 33 I, divided by 23, divisible by 28.So these three add to meet the conditions, but not necessarily the minimum value, how to find the minimum value%LCM (23,28,29) can be.Code:#include Copyright NOTICE: This article for Bo Master original
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