replay backpack

POJ 1276 Cash Machine (multiple backpack)http://poj.org/problem?id=1276Test Instructions :There are n currencies, with denominations and quantities of val[i] and num[i] respectively. Now give an M-value, and ask you what is the largest and not more than m of the amount that you can make up of the above currency?Analysis :Obvious multi-knapsack problem.Dp[i][j]==x that the maximum value of the money in the Initialize: DP is full 0.We carry out the sub-

Description Given a set of n items, each with a weight w[i] and a value v[i], determine a way to choose the items into a knapsack so T Hat The total weight are less than or equal to a given limit B and the total value is as large as possible. Find the maximum total value. (Note this each item can is only chosen once). Input The ' The ' contains the ' the ' indicating to the number of test cases. For the all test case, the the contains the integers n and B. Following n lines provide the informat

}. Mehrdad can ' t invite all of the hoses from the ' the one because their total weight are >, thus the best way is to Choose the "Hos" from the "the" and "only one" to the second group. The total weight is 8, and the total beauty would be 7. Before we solve this problem, let's take a look at the packet knapsack problem: There are n items and a backpack with a capacity of V. The cost of item I is c[i], value is w[i]. These items are divided into gro

Some of the effects are shown first:The backpack is used to store the characters acquired in the game, the box is used to temporarily save the items (only save function), the role panel is used to simulate to the character equipment, weapons, costumes, etc., the rightmost red font panel is used to display the current equipment under the character of the sum of the various attributes. The Trader panel function is mainly used to give players to buy item

I'm the only one who thinks this test instructions difficult to understand ... First give a few sets of data, each set of data is the total catch probability p (the total probability of the final estimate must be less than he, or be caught), and then is to rob the number of banks N. Then n rows, each row is the bank can rob the amount of money m[i] and the probability of being caught p[i], to find the maximum probability of escape. The greater the probability of being caught, the smaller the pr

. You can understand the two models thoroughly and then look at other models. This will definitely get twice the result with half the effort. A special topic was introduced during the course of reading the 9-pack lecture. There were about 26 topics, mainly HDU and poj, which were difficult and easy to answer. This album mainly explained these questions, there are also some simple questions about the UVA backpack that will be added to this album. This

a value of 13 (quality 5). Now let's take a look at the record table to solve this problem:MwOID 0 1 2 3 4 5 6 7 00 0 0 0 0 0 0 01 21 0 2 2 2 2 2 2 23 12 0 2 2 2 3 3 3 35 103 0 2 2 2 3 Ten A A4 114 0 2 2 2 One - - -The table fills the line from left to right and then fills the next line from left to right. Where the Green line is the maximum selection of the item's range subscript OID (for example, oid=2 is selected from two items numbered 1, 2), and the red

Test Instructions:LinkMethod:Six-dimensional backpack +burnside lemmaparsing:Very fun a Burnside/polya problem result I see since this problem has color limitations, then directly think of the card that problem. Got a backpack or something. There are 24 ways to rotate the cube. Face Center Rotation There are 4 4 4 displacement (90°) with 2 2, 2, 2 2 of Displacement (180°) has 2 4 4 of the displacement of th

P04: Mixed backpack Problems If you mix p01, p02, and P03. That is to say, some items can be taken only once (01 backpack), some items can be taken unlimited times (full backpack), and some items can be taken up to a maximum of times (multiple backpacks ). How should we solve it? 01 mixing a backpack with a full

need to add one more dimension. Dp[i][j] Represents the maximum value of using the weight of I, Volume J, the Code is as follows: for (i=1; i) for (j=vv;j>=v[i];j--) for (k=gg;k>=g[i];k--) if (f[j][k]t[i]) f[j][k]=f[j-v[i]][k-g[i]]+t[i];An example:01 Backpack ideas, although the specific implementation may be a little differentYou can use a two-dimensional array, dp[i][j], to get the first gar

01 Backpack (Zeroonepack): There are n items and a backpack with a capacity of V, each of which has only one item . The cost of article I is c[i], the value is w[i]. The sum of the values is maximized by solving which items are loaded into the backpack.Full Backpack (completepack): There are n items and a backpack wit

maximum weight of the last itemSave data that has already been recordedreturn dp[i][j]=res;}int main () {while (scanf ("%d%d", n,w) ==2) {Memset (Dp,-1,sizeof (DP));for (int i=0;iscanf ("%d%d", w[i],v[i]);printf ("%d\n", rec (0,w));}return 0;}/************************************************ 2nd notation, recursive expression ************************************************** **/#include #include int n,w;int v[100],w[100];DP for assistance Arrayint dp[100][100];int max (int n,int m) {Return n>m

format:Cash N N1 D1 n2 D2 ... nN DNwhere 0 OutputFor each set of data the program prints the result to the standard output on a separate line as shown in the examples Belo W.Sample Input735 3 4 6 5 3 350633 4 ten 6 1 5 0 1735 3Sample Output73563000HintThe first data set designates a transaction where the amount of cash requested is @735. The machine contains 3 bill denominations:4 bills of @125, 6 bills of @5, and 3 bills of @350. The machine can deliver the exact amount of requested cas

Topic links\ (description\)Each point has a cost Si and value pi, which requires selecting some connected blocks with a root, the total size is k, making \ (\frac{∑pi}{∑si}\) the largest\ (solution\)01 Fractional plan, then DP, set F[I][J] indicates the maximum weight of the I subtree selected J and, direct violent backpack transfer can beWhen enumerating the number of child nodes selected, assume X has 1.2.3.4 four child nodes with a complexity of \

Cash Machine Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 26954 Accepted: 9533 Main topic:There are a variety of currencies with different denominations. Each denomination has a different number of currencies, please find out the amount of the nearest and less equal to the given number cash that can be used to make the money. multiple backpack turn 0 1 backpackFor the first

/* is a multi-backpack problem, in fact, I still do not understand the backpack, but with the dynamic equation of memory can be played can be AC code, but also strange */#include

This topic just began to think for a while, because it is a tree-like DP topic, so did not see it is 01 backpack (the focus is to reverse), reverse this point has not been thought out why, because the treasure only one, and 01 backpack is the same meaning (actually I now I do not want to understand that since it is already two-dimensional, And why to reverse it), the state transfer equation is Dp[u][j]=max

group of data has two positive integers n,m (0In the following M-line, each row has two data ai (integer), and Bi (real) represents the application fee for the I-school and the probability of getting an offer.The last entry has two 0.Output each set of data corresponds to an export, indicating the maximum probability that speakless may get at least one offer. Expressed as a percentage, accurate to one decimal place.Sample Input 10 3 4 0.1 4 0.2 5 0.3 0 0 Sample Output 44.0% Hint You should use

http://acm.hdu.edu.cn/showproblem.php?pid=1114 Test instructions: The piggy bank can put some small money into it, but it doesn't know how much money is in it after a long time, unless you break it. Now given the weight of the empty jar and the maximum capacity, and then give the value and weight of each coin, we have to confirm the minimum amount of money in the jar without breaking it. Idea: very close to life. There is no limit to the number of coins, so it is a complete

Ask everyone about a deformed backpack. there are N kinds of items and a backpack with a capacity of V. There is also a threshold T. A maximum of n [I] items are available for the I-th item. the cost per item is c [I] and the value is w [I]. Solving which items are loaded into a backpack can make the total cost of these items not exceed the capacity of the